All categories

3 years ago

What is sound wave and examples

1 answer:

3 0

★ « what is sound wave and examples » ★

A sound wave is the pattern of disturbance caused by the movement of energy traveling through a medium (such as air, water, or any other liquid or solid matter) as it propagates away from the source of the sound. The source is some object that causes a vibration, such as a ringing telephone, or a person's vocal chords.

hope it helps

You might be interested in

an astronaut weighs 8.00x10^2 on the surface of earth. what is the weight of the astronaut 6.37x10^6 meters above the surface of

Marta_Voda [28]

To solve this problem, we use the Law of Universal Gravitation:

F = Gm1m2/d^2

where m1 and m2 are two objects. In this case, earth and man. d is the distance between the objects. Lastly, G is the gravitational constant. Since the mass of the earth and man are constant, this is lumped up with G into k. The equation would be:

F = k/d^2
k = Fd^2
$F_{1} d_{1} ^{2} =F_{2} d_{2} ^{2}$

The radius of earth, d1, is equal to 6.371E+6 m. Thus, d2 = 2d1

(8E+2)(d1)^2 = F2(2d1)^2

(8E+2)(d1)^2 = 4F2(d1)^2

(8E+2)=4F2
F2 = 200 Newtons

4 0

3 years ago

Force is applied to an object and the object is moved over a distance in the same direction of the applied force" is the definit

just olya [345]

Answer: The correct answer is "work".

Explanation:

The expression for the work done in terms of force and displacement is as follows;

W= Fd

Here, W is the work done, F is the applied force and d is the displacement.

If the force is applied to an object and the object is displaced to some distance then the work is done.

It is given in the problem that force is applied to an object and the object is moved over a distance in the same direction of the applied force". The given statement is the definition of work. The work done can be zero, negative and positive. In the given case, the positive work is said to be done as the direction of the applied force and the distance moved by the object are same.

Therefore, the correct option is (d).

7 0

3 years ago

Read 2 more answers

14) What is the velocity of a wave 5.35 x 10 cm long with a frequency of 16kHz

JulijaS [17]

Answer:

wavelength= 5.35×10cm=0.535m

f= 16000hz

v= wavelength × f= 0.535×16000=8560m/sec

6 0

3 years ago

A capacitor of capacitance 4 µF is discharging through a 2.0-MΩ resistor. At what time will the energy stored in the capacitor b

Lynna [10]

Answer:

Explanation:

Given that,

The capacitance of the capacitor is

C = 4 µF

Discharging through a resistor of resistance

R = 2 MΩ

Time the energy stored in the capacitor be one-third of its initial energy

i.e. u(E)_ final = ⅓u(E)_initial

U / Uo = ⅓

Energy stored in a capacitor (discharging) can be determined using

U = Uo•RC•exp(-t/RC)

U / Uo = -RC exp(-t/RC)

U / Uo = ⅓

RC = 2 × 10^6 × 4 × 10^-6 = 8s

⅓ = 8 exp( -t / 8)

Divide both side by -8

1/24 = exp(-t/8)

Take In of both sides

In(1/24) = In•exp(-t/8)

-3.1781 = -t / 8

t = -3.1781 × -8

t = 25.42 seconds

It will take 25.42 seconds for he capacitor to be ⅓ of it's initial energy

3 0

4 years ago

A horse trots away from its trainer in a straight line, moving 38m away in 9.0s. It then turns abruptly and gallops halfway back

alekssr [168]

Answer:

a)The average speed of the horse is 5.3 m/s.

b)The average velocity of the horse is 1.8 m/s

Explanation:

Hi there!

a) The average speed (a.s) is calculated as the traveled distance (d) divided the time in which that distance was covered (t):

a.s = d/t

The distance covered by the horse is 38 m away from the trainer and then halfway (38/2 m) back:

d = 38 m + 38/2 m = 57 m

The time it took the horse to cover that distance was 9.0 s plus 1.8 s on the way back:

t = 9.0 s + 1.8 s = 10.8 s

Then the avereage speed will be:

a.s = 57 m / 10.8 s

a.s = 5.3 m/s

The average speed of the horse is 5.3 m/s.

b) The average velocity (a.v) is calculated as the displacement (Δx) divided the time (t) in which that displacement took place.

a.v = Δx/t

The displacement is calculated as the distance between the final position and the initial position:

Δx = final position - initial position

The horse moved 38 m away from the trainer (in the positive direction) and then returned 19 m (the horse moved 19 m in the negative direction). The final position of the horse is 19 m away from the trainer (the origin of the frame of reference). Then, the displacement will be:

Δx = final position - initial position

Δx = 19 m - 0 m (notice that the horse started from the origin, i.e., the trainer).

Δx = 19 m

And the average velocity will be:

a.v = Δx/t

a.v = 19 m / 10.8 s

a.v = 1.8 m/s

The average velocity of the horse is 1.8 m/s

4 0

3 years ago