Answer:
(a) A = 0.650 m
(b) f = 1.3368 Hz
(c) E = 17.1416 J
(d) K = 11.8835 J
U = 5.2581 J
Explanation:
Given
m = 1.15 kg
x = 0.650 cos (8.40t)
(a) the amplitude,
A = 0.650 m
(b) the frequency,
if we know that
ω = 2πf = 8.40 ⇒ f = 8.40 / (2π)
⇒ f = 1.3368 Hz
(c) the total energy,
we use the formula
E = m*ω²*A² / 2
⇒ E = (1.15)(8.40)²(0.650)² / 2
⇒ E = 17.1416 J
(d) the kinetic energy and potential energy when x = 0.360 m.
We use the formulas
K = (1/2)*m*ω²*(A² - x²) (the kinetic energy)
and
U = (1/2)*m*ω²*x² (the potential energy)
then
K = (1/2)*(1.15)*(8.40)²*((0.650)² - (0.360)²)
⇒ K = 11.8835 J
U = (1/2)*(1.15)*(8.40)²*(0.360)²
⇒ U = 5.2581 J
C. Magnetism
It is a physical property, not a chemical property.
The amount of heat transferred from the ocean to the atmosphere as latent heat than sensible heat will be 10 times as much.
Latent heat and sensible heat are defined as follows:
- Latent heat: It is the heat that leaves/enters a system during a process where the temperature of the system stays constant.
Examples are phase changes where the latent heat from the system leaves (exothermic) or enters a system (endothermic).
- Sensible heat: It is the heat that enters or exits a system when the temperature of the system is not constant. The entire heat flows through the two systems and in order to do so it requires a temperature difference between the systems.
Thus, the amount of heat transferred from the ocean to the atmosphere as latent heat than sensible heat will be 10 times as much.
Learn more about latent and sensible heat here:
<u>brainly.com/question/13499849</u>
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Answer:
Explanation:
The magnetic field strength is given by:
where
is the vacuum permeability
I is the current
r is the distance from the wire
In this problem,
I = 6.5 A
r = 6.3 cm = 0.063 m
So, the magnetic field strength is
To solve this problem it is necessary to apply the concepts related to Ohm's Law to find the voltage in the case of direct current. While for the Alternate current we use the concept of RMS voltage.
PART A) In the case of DC we have to,
V=IR
Where,
I = Current
R = Resistance
Where the current is 60mA y the resistance is 
, then the potential would be
In the case of DC we have that the current and the RMS voltage is,
The potential in AC then is,
