Answer:
The correct answer is: waxing gibbous, 3 days
Explanation:
Waning quarter moon: hair removal time and bangs cuts.
The growing quarter as a moment of growth, development and evolution. On the contrary, the waning moon is associated with a time of completion, debugging or liquidation of pending issues.
We must take advantage of the influence of the lunar cycle in our favor according to the action we are going to take. If you have trouble growing your hair, try to go to the hairdresser in a crescent moon: it will grow faster. It is no nonsense. Since I cut my bangs to the Cleopatra, the touch-ups last me for another 1-1.5 weeks. As I reviewed the bangs in a growing room, in just a couple of weeks I was returning to the hairdresser.
That affects hair removal. There are many people who take appointments to the beautician to shave by consulting the lunar calendar. The hair removal done as soon as the dwindling is the best because it lasts longer, lasts for another week until the next appointment.
A. True. You can use displacement to determine the volume of solids and liquids.
Your answer should be 9.7 :)
Answer:
1. 
2. 
3. 
Explanation:
Given:
- mass of slinky,
- length of slinky,
- amplitude of wave pulse,
- time taken by the wave pulse to travel down the length,
- frequency of wave pulse,
1.
2.
<em>Now, we find the linear mass density of the slinky.</em>
We have the relation involving the tension force as:
3.
We have the relation for wavelength as:
Answer:
Explanation:
The change is as follows
P₁ V₁ to 3P₁, V₁ ( constt volume ) --- first process
3P₁,V₁ to 3P₁ , 5V₁ ( constt pressure ) ---- second process
In the first process Temperature must have been increased 3 times . So if initial temperature is T₁ then final temperature will be 3 T₁
P₁V₁ = n R T₁ , n is no of moles of gas enclosed.
nRT₁ = P₁V₁
Heat added at constant volume = n Cv ( 3T₁ - T₁)
= n x 5/3 R X 2T₁ ( for diatomic gas Cv = 5/3 R)
= 10/3 x nRT₁
= 10/3x P₁V₁
In the second process, Temperature must have been increased 5 times . So if initial temperature is 3T₁ then final temperature will be 15 T₁
Heat added at constant pressure in second case
= n Cp ( 15T₁ - 3T₁)
= n x 7/3 R X 12T₁ ( For diatomic gas Cp = 7/3 R)
= 28 x nRT₁
= 28 P₁V₁
