A treasure chest full of silver and gold coins is being lifted from a pirate ship to the shore using two ropes as shown in the f
igure. The mass of the treasure chest is 75.6 kg.
If the tension in rope A is 7.42x10^2 N and the tension rope B carries is 7.52x10^2 N, what is the tension in rope C?
If the tension in rope A is 7.42x10^2 N and the tension rope B carries is 7.52x10^2 N, what is the tension in rope C?
1 answer:
You might be interested in
Answer:
mu = 0.56
Explanation:
The friction force is calculated by taking into account the deceleration of the car in 25m. This can be calculated by using the following formula:
v: final speed = 0m/s (the car stops)
v_o: initial speed in the interval of interest = 60km/h
= 60(1000m)/(3600s) = 16.66m/s
x: distance = 25m
BY doing a the subject of the formula and replace the values of v, v_o and x you obtain:
with this value of a you calculate the friction force that makes this deceleration over the car. By using the Newton second's Law you obtain:
Furthermore, you use the relation between the friction force and the friction coefficient:
hence, the friction coefficient is 0.56
The age of a man whose normal blood pressure measures 123 mm of hg
9 years
<h3>What is Quadratic equation ?</h3>A quadratic equation as an equation of degree 2, meaning that the highest exponent of this function is 2. The standard form of a quadratic equation is y = a + bx + c, where a, b, and c are numbers and a cannot be 0
P(A) = 0.006 - 0.02a + 120
123 = 0.006- 0.02a + 120
0=0.006 - 0.02a - 3
you can use the quadratic equation formula to solve for the man's age.
A = (-b ± () ) / (2a)
A = (0.02 ± / (2*0.006)
A = (0.02 ± ) / 0.012
A = 9 , -5.67
Age of the man will be 9 years
To learn more about quadratic equation here
brainly.com/question/17177510?referrer=searchResults
#SPJ4