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3 years ago

What object or class of objects makes up most of the solar system’s mass?

2 answers:

8 0

Solar system is the gravitationally bound system that consists of the sun and the objects that orbit around it directly or indirectly. These objects includes the planets which orbit the sun directly an other small objects such as meteoroids, asteroids, satellites of the planets and numerous comets. The sun makes up most of the solar system' mass.

Serggg [28]3 years ago

7 0

<span>The Sun makes up most of our solar system's mass. It accounts for about 98% of the mass of the whole solar system. Other objects such as planets, moons, asteroids and comets amount to only about 2% of the solar system's mass.</span>

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If you push any floating object down from equilibrium and release it, it bobs up and down. That looks like an oscillation, so le

GarryVolchara [31]

Answer:

$F_{y}$ = ( ρ_fluid g A) y

Explanation:

This exercise can be solved in two parts, the first finding the equilibrium force and the second finding the oscillating force

for the first part, let's write Newton's equilibrium equation

B₀ - W = 0

B₀ = W

ρ_fluid g V_fluid = W

the volume of the fluid is the area of the cube times the height it is submerged

V_fluid = A y

For the second part, the body introduces a quantity and below this equilibrium point, the equation is

B - W = m a

ρ_fluid g A (y₀ + y) - W = m a

ρ_fluid g A y + (ρ_fluid g A y₀ -W) = m a

ρ_fluid g A y + (B₀-W) = ma

the part in parentheses is zero since it is the force when it is in equilibrium

ρ_fluid g A y = m a

this equation the net force is

$F_{y}$ = ( ρ_fluid g A) y

we can see that this force varies linearly the distance and measured from the equilibrium position

8 0

3 years ago

A SQUARE induction coil with a side length 3 cm and 400 windings, is placed perpendicularly in a uniform magnetic field and then

Lelu [443]

The result will be E1=E2>E4>E3

When the plane of the armature of an a.c. dynamo is parallel to the lines of force of the magnetic field, the amplitude of the induced e.m.f. is at its greatest. Additionally, the rate of change of the magnetic flux associated with the armature is at its greatest. As a result, in this orientation, the e.m.f. induced in the armature is greatest.

The EMF's amplitude is equal to Nr2B. N is the number of turns, and r is the square's half-side.

In example 3, the axis is perpendicular to the magnetic field, hence the flux is zero and the amplitude is zero as a result.

Case 4 has an axis that falls between types 1, 2, and 3.

Here, we must consider the angular velocity's x and y components.

Component in the x direction will be zero.

Additionally, the new angular velocity will be 2w because it is exactly halfway between x and y.

So now put these numbers in actual formula. The result will be E1=E2>E4>E3

Learn more about Magnetic field here-

brainly.com/question/14848188

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4 0

2 years ago

A 10n force is applied to a 25kg mass to slide it across a frictional surface. What is the acceleration of the mass?

klasskru [66]

Answer: a = 0.4m/s^2 - 9.8*c where c is the coefficient of kinetic friction of the surface

Explanation: We know that, by the second Newton's law, a = F/m

where a is the acceleration, F is the net force and m is the mass of the object.

Then, if the surface is frictionless, the total force applied in the object is 10N, and the mass of the object is 25kg, so the acceleration is:

a =10N/25kg = 0.4m/s^2.

But if the surface is frictional, there will be a force of friction applied in the mass (this depends on the coefficient of friction and the weight of the mass), this means that the acceleration will be reduced.

If = -(9.8*25)*c

where c is a number that is bigger than 0 and smaller than 1, is called the coefficient of kinetic friction.

So the total force is now:

F = (10 - 9.8*25*c)

Then, the acceleration in a frictional surface is equal to:

a = (10 - 9.8*25*c)/25 = 0.4m/s^2 - 9.8*c

6 0

4 years ago

Read 2 more answers

Pls I need help ASAP

umka21 [38]

Answer:

i dont undertsnad what do u ned hep wit?

Explanation:

3 0

3 years ago

A dvd drive has a maximum speed of 72000 revolutions per minute. if a dvd has a diamter of 12 what is the linear speed

Brilliant_brown [7]

The question isn't clear enough, I think it ask us to calculate the linear speed of a point at the edge of the DVD.
Now let's imagine we're a point at the edge of the DVD, we're undergoing a circular motion. Each minute we will complete a circular track 7200 times, now we need to know the distance we travel each turn. The perimeter of the DVD, a circular object is:
$P=2\pi.R$
Know recall that:
$v=\frac{d}{t}$
We now need to know how much distance is traveled during a minute or 60 seconds:
$D=7200\times 2\pi\times R$
Finally we divide this result with t=60 seconds:
$v=\frac{7200\times2\pi\times R}{60}
\\
R=\frac{12}{2}=6
$
$v\approx 4523.89 \frac{units}{second}$
Where the distance units were named units as the length unit is not specified in this exercise.<span />

7 0

4 years ago