What kind of mirror is used in automobiles and trucks

1. Driving at slower speeds than traffic flow _____________ .

r-ruslan [8.4K]

The correct option is (D). The strength of electric field depends on the amount of charge that produces the field as well as the distance from the charge.

Further Explanation:

The electric field intensity at a point is the measure of the force exerted by a charge particle on another charge particle in the particular area of its strength.

The electric field intensity at a distance $d$ due to a static charge having charge $q$ is directly proportional to the amount of charge and inversely proportional to the square of the distance between them.

The Electric field intensity due to a charge is given as:

$E = \dfrac{1}{{4\pi {\varepsilon _0}}}\frac{q}{{{r^2}}}$

Here, $E$ is the electric field intensity, $q$ is the amount of charge and $r$ is the distance of the charge from the point.

The above expression of electric field shows that the electric field intensity at a point depends on the amount of charge as well as the distance of the point from the charge.

Thus, the correct option is (D). The strength of electric field depends on the amount of charge that produces the field as well as the distance from the charge.

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Answer Details:

Grade: Senior school

Subject: Physics

Chapter: Electrostatics

Keywords: Strength, electric field, charge, distance, electric field intensity, magnitude of charge, electrostatic, test charge, kq/r^2.

7 0

4 years ago

Read 2 more answers

What tells you how far/how tall/how long something is? *The answer is 6-letters and the second letter is a "e" and the fifth let

rosijanka [135]

Length is the answer because it's six letters

4 0

4 years ago

A rubber ducky is placed 20 cm from a thin convex lens with a focal length of 15 cm. Which statement correctly describes the nat

blondinia [14]

I believe the answer is B, a real and inverted image is formed on the side of the lens opposite the rubber ducky. The focal length is 15 cm and therefore the center of curvature (2F) will be 30 cm. When the object is placed between F and 2F (in this case 20 cm) in front of a convex lens, an inverted, real image is formed on the other side of the lens.

6 0

3 years ago

Read 2 more answers

A 570 kg elevator accelerates downwards at 1.5 m/s2 for the first 13 m of its motion.

jeka94

Mass of the elevator (m) = 570 Kg
Acceleration = 1.5 m/s^2
Distance (s) = 13 m
Let the force be F.
We know, F = ma,
Therefore, F = (570 × 1.5) N = 855 N
Angle between distance and force (θ) = 0°
We know, work done = F s Cos θ
Therefore, work done by the cable during this part
= (855 × 13 × Cos 0°) J
= (855 × 13 × 1) J
= 11115 J

Answer:

11115 J

Hope you could get an idea from here.

Doubt clarification - use comment section.

6 0

3 years ago

Conservation of Momentum No one likes you little trolls please send an actual answer

Olin [163]

Hello!

This is an example of an inelastic collision, where the two objects "stick" to each other after their collision. (The Goalkeeper CATCHES the puck).

We can write out the conservation of momentum formula:

m1vi + m2vi = m1vf + m2vf

Let:

m1 = mass of puck

m2 = mass of the goalkeeper

We know that the initial velocity of the goalkeeper is 0, so:

m1vi + m2(0) = m1vf + m2vf

m1vi = m1vf + m2vf

The final velocities will be the same, so:

m1vi = (m1 + m2)vf

Plug in the given values:

(0.16)(40)/ (0.16 + 120) = vf ≈ 0.0533 m/s

Using the equation for momentum:

p = mv

The object with the LARGER mass will have the greater momentum. Thus, the Goalkeeper has the largest momentum as p = mv; a greater mass correlates to a greater momentum since the velocity is the same between the two objects. The puck would have a momentum of p = (.16)(0.0533) = 0.008528 kgm/s, whereas the goalkeeper would have a momentum of

p = (120)(0.0533) = 6.396 kgm/s.

3 0

2 years ago