Answer:
a) Height of the antenna (in m) for a radio station broadcasting at 604 kHz = 124.17 m
b)Height of the antenna (in m) for radio stations broadcasting at 1,710 kHz =43.86 m
Explanation:
(a) Radiowave wavelength= λ = c/f
As we know, Radiowave speed in the air = c = 3 x 10^8 m/s
f = frequency = 604 kHz = 604 x 10^3 Hz
Hence, wavelength = (3x10^8/604x10^3) m
λ
= 496.69 m
So the height of the antenna BROADCASTING AT 604 kHz = λ /4 = (496.69/4) m
= 124.17 m
(b) As we know , f = 1710 kHz = 1710 x 10^3 Hz (1kHZ = 1000 Hz)
Hence, wavelength = λ = (3 x 10^8/1710 x 10^3) m
λ= 175.44 m
So, height of the antenna = λ /4 = (175.44/4) m
= 43.86 m
Answer:
Sometimes may cause involuntary responses like twitching
Explanation:
Answer:
1.35 m
Explanation:
Taking down to be positive, given:
Δx = Δy / tan 30.0º
v₀ₓ = 4.50 m/s
v₀ᵧ = 0 m/s
aₓ = 0 m/s²
aᵧ = 10 m/s²
Find: Δy
First, find the time it takes to land in terms of Δy.
Δy = v₀ t + ½ at²
Δy = (0 m/s) t + ½ (10 m/s) t²
Δy = 5t²
Next, find Δx in terms of t.
Δx = v₀ t + ½ at²
Δx = (4.50 m/s) t + ½ (0 m/s) t²
Δx = 4.50t
Substitute:
Δy = 5 (Δx / 4.50)²
20.25 Δy = 5 (Δx)²
4.05 Δy = (Δx)²
4.05 Δy = (Δy / tan 30.0º)²
4.05 Δy = 3 (Δy)²
1.35 = Δy
The basketball was thrown from an initial height of 1.35 m.
Graph: desmos.com/calculator/ujuzdo9xpr
Answer:
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