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sergey [27]
3 years ago
10

What does variable mean

Chemistry
1 answer:
DedPeter [7]3 years ago
4 0
In an experiement things that are changing are called variables.
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Need help asap please!
Andrei [34K]

Answer:

B

Explanation:

because polarity of the water molecules is due to the B. deflection of the hydrogen atoms by the lone pair of electrons.

4 0
3 years ago
How do ethical concerns affect scientific research
Gwar [14]

Answer:

Ethical concerns affect scientific research by adding boundaries to what can and cant be experimented on. An example is that its socially unacceptable to experiment on humans because its considered wrong and horrific, even at the expense of learning more about human nature and/or the human body.

7 0
3 years ago
Which of the following statements correctly explains how latitude affects temperature?
dusya [7]

Answer:

It's 1, places that are closer to the equator receive more direct sunlight and have

Explanation:

7 0
2 years ago
The reaction for the formation of gaseous hydrogen fluoride (HF) from molecular hydrogen (H2) and fluorine (F2) has an equilibri
mestny [16]

Answer:

[H2]eq = 0.0129 M

[F2]eq = 1.0129 M

[HF]eq = 0.9871 M

Explanation:

  • H2(g) + F2(g) ↔ 2HF(g)

∴ Ke = [HF]² / [H2]*[F2] = 1.15 E2

experiment:

∴ n H2 = 3.00 mol

∴ n F2 = 6.00 mol

∴ V sln = 3.00 L

⇒ [H2]i = 3.00 mol / 3.00 L = 1 M

⇒ [F2]i = 6.00 mol / 3.00 L = 2 M

        [ ]i    change      [ ]eq

H2     1         1 - x         1 - x

F2     2        2 - x         2 - x

HF     -            x              x

⇒ K = (x)² / (1 - x)*(2 - x) = 1.15 E2

⇒ x² / (2 - 3x + x²) = 1.15 E2 = 115

⇒ x² = (2 - 3x + x²)(115)

⇒ x² = 230 - 345x + 115x²

⇒ 0 = 230 - 345x + 114x²

⇒ x = 0.9871

equilibrium:

⇒ [H2] = 1 - x = 1 - 0.9871 = 0.0129 M

⇒ [F2] = 2 - x = 2 - 0.9871 = 1.0129 M

⇒ [HF] = x = 0.9871 M

5 0
3 years ago
How will adding NaCl affect the freezing point of a solution?
lord [1]

Answer is: adding NaCl will lower the freezing point of a solution.

A solution (in this example solution of sodium chloride) freezes at a lower temperature than does the pure solvent (deionized water).

The higher the solute concentration (sodium chloride), freezing point depression of the solution will be greater.

Equation describing the change in freezing point:  

ΔT = Kf · b · i.

ΔT - temperature change from pure solvent to solution.

Kf - the molal freezing point depression constant.

b -  molality (moles of solute per kilogram of solvent).

i - Van’t Hoff Factor.

Dissociation of sodium chloride in water: NaCl(aq) →  Na⁺(aq) + Cl⁻(aq).

3 0
3 years ago
Read 2 more answers
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