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pav-90 [236]
3 years ago
13

(Science) Match each word with its example

Physics
1 answer:
MAVERICK [17]3 years ago
6 0
Velocity_slowing down_284cm per sec sw
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what will be the effect on the acceleration due to gravity of the earth if it is compressed to a the size the moon?​
GuDViN [60]

Answer:

it gravitional pull on earth will increased becauste it is compress to a form of moon which is comperatively smaller so the gravitonal pull on per cm of earth will incrased so we can say that there will be change in acceleration due to gravity

7 0
3 years ago
Read 2 more answers
Red light of wavelength 633 nmnm from a helium-neon laser passes through a slit 0.360 mmmm wide. The diffraction pattern is obse
777dan777 [17]

Answer:

      Δy= 5,075 10⁻⁶ m

Explanation:

The expression that describes the interference phenomenon is

      d sin θ = (m + ½) λ

As the observation is on a distant screen

     tan θ = y / x

     tan θ= sin θ/cos θ

As in ethanes I will experience the separation of the vines is small and the distance to the big screen

          tan θ = sin θ

Let's replace

     d y / x = (m + ½) λ

The width of a bright stripe at the difference in distance  

     y₁ = (m + ½) λ x / d

     m = 1

      y₁ = 3/2 λ x / d

Let's use m = 1, we look for the following interference,

             m = 2

             y₂ = (2+ ½) λ x / d

The distance to the screen is constant x₁ = x₂ = x₀

The width of the bright stripe is

           Δy = λ x / d (5/2 -3/2)

           Δy = 630 10⁻⁹ 2.90 /0.360 10⁻³ (1)

           Δy= 5,075 10⁻⁶ m

8 0
3 years ago
What current flows through a 2.60-cm-diameter rod of pure silicon that is 20.5 cm long, when 1.00 ✕ 103 V is applied to it? (Suc
Virty [35]

Answer:

1.13 mA

Explanation:

Length of wire L = 20.5 cm = 0.205m

Radius of wire r = 2.60/2 = 1.3cm = 0.0130m

Voltage V = 1 × 10³ V

Resistivity of pure silicon p = 2300 Ohms • m

Cross sectional area of the wire

A = pi × r² = pi × (0.013)² = 5.307 × 10 ^-4 m²

Resistance of the material

R = p• L/A

= 2300 • 0.205/5.307 × 10^-4 = 0.888 × 10⁶ Ohms

Using Ohms Law

R = V/ I

I = V/R

I = 10³/0.888 × 10⁶

= 0.001126 A

= 1.13 mA

5 0
4 years ago
A proton moves with a velocity of v with arrow = (3î − 5ĵ + k) m/s in a region in which the magnetic field is B with arrow = (î
Allisa [31]

Answer:

The magnitude of the magnetic force this particle experiences is 2.6\times10^{-9}\ N.

Explanation:

Given that,

Velocity v= (3i-5j+k) m/s

Magnetic field B=(i+2j-k) T

We need to calculate the value \vec{v}\times\vec{B}

(\vec{v}\times\vec{B})=3i+4j+11k

We need to calculate the magnitude of the magnetic force this particle experiences

Using formula of magnetic force

\vec{F}=q(\vec{v}\times\vec{B})

Put the value into the formula

\vec{F}=1.6\times10^{-19}\times(3i+4j+11k)

\vec{F}=(4.8i+6.4j+1.76k)\times10^{-19}

|F|=2.6\times10^{-9}\ N

Hence, The magnitude of the magnetic force this particle experiences is 2.6\times10^{-9}\ N.

7 0
3 years ago
A thermometer can be used _______.
Colt1911 [192]
The answer is D.All of the above
4 0
3 years ago
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