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choli [55]
2 years ago
10

1.

Chemistry
2 answers:
Talja [164]2 years ago
8 0
Above is the answer
monitta2 years ago
3 0

Answer:

Answer : (1) :-

Volume of water filled in the pycnometer is given as = 9.9872 mL.

Mass of pycnometer when filled with water = 23.1148 g.

Mass of empty pycnometer = 13.1455 g.

So, mass of water = (23.1148 - 13.1455) g. = 9.9693 g.

We know that,

<em>    Density = Mass / Volume = (9.9693 g.) / (9.9872 mL) = </em>0.998 g/mL.

<u>It is observed that the density of water is evaluated to be 0.998 g/mL. We know that, at 4℃ the density of water becomes maximum i.e. 1 g/mL. On the other hand the temperature at which the density of water is 0.998 g/mL is 0℃. Therefore, it can be concluded that the experiment was performed at a temperature of 0℃.</u>

<u />

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The ph of a solution prepared by mixing 45.0 ml of 0.183 m koh and 35.0 ml of 0.145 m hcl is ________.
Naddika [18.5K]

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  • We should calculate the no. of millimoles of KOH and HCl:

no. of millimoles of KOH = (MV)KOH = (0.183 M)(45.0 mL) = 8.235 mmol.

no. of millimoles of HCl = (MV)HCl = (0.145 M)(35.0 mL) = 5.075 mmol.

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