1.

Chemistry

2 answers:

Talja [164]3 years ago

8 0

Above is the answer

monitta3 years ago

3 0

Answer:

Answer : (1) :-

Volume of water filled in the pycnometer is given as = 9.9872 mL.

Mass of pycnometer when filled with water = 23.1148 g.

Mass of empty pycnometer = 13.1455 g.

So, mass of water = (23.1148 - 13.1455) g. = 9.9693 g.

We know that,

Density = Mass / Volume = (9.9693 g.) / (9.9872 mL) = 0.998 g/mL.

It is observed that the density of water is evaluated to be 0.998 g/mL. We know that, at 4℃ the density of water becomes maximum i.e. 1 g/mL. On the other hand the temperature at which the density of water is 0.998 g/mL is 0℃. Therefore, it can be concluded that the experiment was performed at a temperature of 0℃.

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Draw the structure for 1-nitrobutane, making sure to add all non-zero formal charges.

TiliK225 [7]

The molecular structure of 1-nitrobutane is $C_{4} H_{9} NO_{2}$ . The structure of 1-nitrobutane is shown below.

An atom's formal charge would be determined by the covalent model of chemical bonding, which assumes that almost all chemical bonds include equal sharing of electrons among all atoms, regardless their relative electronegativity.

The structure for 1-nitrobutane, making sure to add all non-zero formal charges

There are four kind of molecule present in 1-nitrobutane and they are carbon, hydrogen , nitrogen and oxygen. Nitrogen is bonded with two oxygen atom out of them one oxygen atom is attached with single bond and second oxygen atom is bonded with double bond. Nitrogen has positive charge whereas oxygen has negative charge.

It is a kind of alkane in with nitro group is attached with alkane group.

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