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Here we have to write a simple equation which describes the action of the enzyme catalase.
The equation is: The concentration of the complex [ES] = ![\frac{[E]0}{1+\frac{Km}{[S]} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5BE%5D0%7D%7B1%2B%5Cfrac%7BKm%7D%7B%5BS%5D%7D%20%7D)
Let us consider an enzyme catalyses reaction E + S ⇄ ES → E + P
Where E, S, ES and P are enzyme, substrate, complex and product respectively.
The concentration of the complex [ES] =
, where
is the Michaelis constant.
[E]₀ and [S] is the initial concentration of enzyme and concentration of substrate respectively.
Answer: The molar concentration of oxygen gas in water is
.
Explanation:
Partial pressure of the
gas = 685 torr = 0.8905 bar
1 torr = 0.0013 bar
According Henry's law:

Value of Henry's constant of oxygen gas at 20 °C in water = 34860 bar


Let the number of moles of
gas in 1 liter water be n.
1 Liter water = 1000 g of water
Moles of water in 1 L 




Molar concentration of oxygen gas in 1 L of water:

The molar concentration of oxygen gas in water is
.
Reflection, refracting, and the energy levels of molecular orbitals
Divide mass by the volume to find density.