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maw [93]
2 years ago
9

An ionic precipitation reaction takes place when aqueous solutions of potassium phosphate and aluminum nitrate are combined in a

beaker.
K3PO4(aq) + Al(NO3)3(aq) →
i. Predict the products and write a balanced chemical equation for the reaction,
including state symbols.
K3PO4(aq) + Al(NO3)3(aq) →
ii. Write the complete balanced ionic equation, including state symbols.
iii. Write the complete balanced net ionic equation, including state symbols.​
Chemistry
1 answer:
larisa86 [58]2 years ago
5 0

Answer:

I hope you can get a good answer

Explanation:

What class is this for?

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Absalon adds 1 g of salt to 1 L of room temperature water (25 °C). Then, he starts a timer and observes what happens. He notices
lana [24]

Answer:

B

Explanation:

I looked it up and found the answer lol

6 0
3 years ago
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Each molecule of table sugar, C12H22O11, contains
Delicious77 [7]
D, because C12 means there's 12 atoms of carbon. 
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What are 4 similarities of Metals, Nonmetals, and Metalloids?
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e o i and a



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7 0
3 years ago
What is [h3o ] in a solution of 0.075 m hno2 and 0.030 m nano2?
Tanya [424]
Answer is: concentration of hydrogenium ions is 9,54·10⁻⁵ M.
c(HNO₂) = 0,075 M.
c(NaNO₂) = 0,035 M.
Ka(HNO₂) = 4,5·10⁻⁵.
This is buffer solution, so use <span>Henderson–Hasselbalch equation:
pH = pKa + log(c(</span>NaNO₂) ÷ c(HNO₂)).
pH = -log(4,5·10⁻⁵) + log(0,035 M ÷ 0,075 M).
pH = 4,35 - 0,33.
pH = 4,02.
<span>[H</span>₃O⁺] = 10∧(-4,02).
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8 0
3 years ago
The enthalpies of formation of the compounds in the combustion of methane, , are CH4 (g): Hf = –74.6 kJ/mol; CO2 (g): Hf = –393.
algol [13]

Answer:

The amount of energy released from the combustion of 2 moles of methae is 1,605.08 kJ/mol

Explanation:

The chemical reaction of the combustion of methane is given as follows;

CH₄ (g) + 2O₂ (g) → CO₂ (g) + 2H₂O (g)

Hence, 1 mole of methane combines with 2 moles of oxygen gas to form 1 mole of carbon dioxide and 2 moles of water vapor

Where:

CH₄ (g): Hf = -74.6 kJ/mol

CO₂ (g): Hf = -393.5 kJ/mol

H₂O (g): Hf = -241.82 kJ/mol

Therefore, the combustion of 1 mole of methane releases;

-393.5 kJ/mol × 1 + 241.82 kJ/mol × 2 + 74.6 kJ/mol = -802.54 kJ/mol

Hence the combustion of 2 moles of methae will rellease;

2 × -802.54 kJ/mol or 1,605.08 kJ/mol.

8 0
3 years ago
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