The number of sulfate ions : 2.2 x 10²³
<h3>Further explanation</h3>
Reaction
Al₂(SO₄)₃⇒2Al³⁺+3SO₄²⁻
mol Al₂(SO₄)₃(MW=342,15 g/mol) :

mol of sulfate ions (SO₄²⁻)

1 mol = 6.02 x 10²³ particles (ions, molecules, atoms), so for 0.366 mol :

To get the ∆S of the reaction, we simply have to add the ∆S of the reactants and the ∆S of the products. Then, we get the difference between the ∆S of the products and the ∆S of the products. If the <span>∆S is negative, then the reaction spontaneous. If the otherwise, the reaction is not spontaneous.</span>
Se
1s^2 2s^2 2p^6 3s^2 3p^6 3d^10 4s^2 4p^4
<span><span><span>Be
1s^2 2s^2
</span></span></span>