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nadezda [96]
3 years ago
15

Why Does A Candle Go Out When You Blow On It ?

Chemistry
2 answers:
Bond [772]3 years ago
5 0
Because of the wind and the cold from ur breath 
Airida [17]3 years ago
4 0
The main reason is the high level of CO₂ that is contained in the breath as well as the effect of the blowing of taking away the air around the candle that is higher in O₂ than the air coming out with the breath
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Based on the graph below, if you chose an alien at random on day 20, what form would it most likely be in?
ArbitrLikvidat [17]

Answer:

A. Thin

Explanation:

i took the test a while back yw <3

4 0
3 years ago
How many grams Kl are needed to prepare 100.mL of 0.55M solution?​
Makovka662 [10]

Answer:

Explanation:

100mL = 0.1L

0.55 M = mol/0.1 L

mol = 0.055 mol

molar mass of KI = 165.998 g

0.055 * 165.998 = 9.13 g of KI

7 0
2 years ago
n unknown metal is either aluminum, iron or lead. If 150. g of this metal at 150.0 °C was placed in a calorimeter that contains
Nitella [24]

Answer : The metal used was iron (the specific heat capacity is 0.449J/g^oC).

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of unknown metal = ?

c_2 = specific heat of water = 4.184J/g^oC

m_1 = mass of unknown metal = 150 g

m_2 = mass of water = 200 g

T_f = final temperature of water = 34.3^oC

T_1 = initial temperature of unknown metal = 150.0^oC

T_2 = initial temperature of water = 25.0^oC

Now put all the given values in the above formula, we get

150g\times c_1\times (34.3-150.0)^oC=-200g\times 4.184J/g^oC\times (34.3-25.0)^oC

c_1=0.449J/g^oC

Form the value of specific heat of unknown metal, we conclude that the metal used in this was iron (Fe).

Therefore, the metal used was iron (the specific heat capacity is 0.449J/g^oC).

6 0
3 years ago
Convert 3.09 x 10~3 m = nm
Dmitriy789 [7]

3090000000nm

since there's 1m = 1000000000nm

6 0
3 years ago
A large piece of jewelry has a mass of 132.6 g. a graduated cylinder initially contains 48.6 ml water. when the jewelry is subme
Simora [160]

Answer:- Density is 10.5 grams per mL and the substance is Silver(Ag).

Solution:-  Mass of jewelry is given as 132.6 g. Initial volume of water in the graduated cylinder is 48.6 mL and the volume becomes 61.2 mL when this jewelry is submerged in the cylinder.

So, the volume of the jewelry = 61.2 mL - 48.6mL = 12.6 mL

We know that, density=\frac{mass}{volume}

Let's plug in the values in the above formula to calculate the density:

density=\frac{132.6g}{12.6mL}

density=10.5\frac{g}{mL}

So, the density of the jewelry is 10.5\frac{g}{mL} .

The substance from which the jewelry is made could easily be identified by comparing the calculated density with the density values given for different substances in the density table.

Looking at the density table, 10.5 grams per mL is the density for silver. So, the jewelry is made up from Silver.

4 0
3 years ago
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