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evablogger [386]
4 years ago
13

I'm confused with this​ I need this ASAP

Physics
1 answer:
Gnoma [55]4 years ago
6 0
I’m pretty sure it’s a
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A molecule that moves across a cell membrane without using the cell’s energy tends to move
zaharov [31]

Answer:answer is b

Explanation:

4 0
3 years ago
A 2190 kg car moving east at 10.5 m/s collides with a 3220 kg car moving east. The cars stick together and move east as a unit a
Bezzdna [24]

To solve this problem it is necessary to apply the concepts related to the conservation of the Momentum describing the inelastic collision of two bodies. By definition the collision between the two bodies is given as:

m_1v_1+m_2v_2 = (m_1+m_2)V_f

Where,

m_{1,2}= Mass of each object

v_{1,2}= Initial Velocity of Each object

V_f= Final Velocity

Our values are given as

m_1 = 2190Kg

v_1 =10.5m/s

m_2 = 3220kg

V_f = 4.74m/s

Replacing we have that

m_1v_1+m_2v_2 = (m_1+m_2)V_f

(2190)(10.5)+(3220)v_2 = (2190+3220)(4.74)

v_2 = 0.8224m/s

Therefore the the velocity of the 3220 kg car before the collision was 0.8224m/s

8 0
4 years ago
What is the acceleration caused by gravity of the planet Earth?
Luda [366]
The general accepted value of acceleration due to gravity, g, is 9.81 m/s^2.

That is an approximation because being the acceleration of gravity due to the attraction of the earth its magnitude will depend on the distance from the point to the center of the planet Earth.

The value of g is determined by using the Newton's Universal Law of gravity:

F = G * m of Earth * m of body / (distance^2)

Wehre {G* m of Earth / (distance^2) } = g

G is a universal constant = 6.67 * 10 ^ -11 N*m^2 / kg^2

m of Earth = 5.98 * 10 ^ 24 kg 

distance = radius of Earth + height of the body

Given the the Earth is not a perfect sphere the radius varies. Also the height of the body varies.

If you take a mean radius of Earth of 6.37*10^6 m

you get

g = 6.67*10^-11 N*m^2/kg^2 * 5.98*10^24kg / (6.37*10^6 m)^2 = 9.83 m/s^2

Again, if you want a more precise value of g, you need to find the exact place where you are and then use the right r.



 
7 0
3 years ago
A 25 pF parallel-plate capacitor with an air gap between the plates is connected to a 100 V battery. A Teflon slab is then inser
fgiga [73]

Answer:

5.3 nC

Explanation:

The initial charge stored on the capacitor is given by:

Q=CV (1)

where

C=25 pF = 25\cdot 10^{-12}F is the capacitance of the capacitor

V=100 V is the potential difference across the capacitor

Substituting numbers into the equation, we have

Q=(25\cdot 10^{-12} F)(100 V)=25\cdot 10^{-10}C=2.5 nC

When the Teflon slab is inserted between the plates, the capacitance of the capacitor is increased as follows:

C'=kC

where k=2.1 is the dielectric constant of the Teflon. Since the voltage V remains constant, this means that the new charge stored by the capacitor (1) will be

Q'=C'V=kCV=kQ

and so

Q'=(2.1)(2.5 nC)=5.3 nC

6 0
3 years ago
One particle, of mass m , moves with a speed v in the x-direction, and another particle, of mass 2 m , moves with a speed v/2 in
Artemon [7]
I hope this helps you! :)

8 0
3 years ago
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