Speed of the tip of the minute hand=V=0.0244 cm/s
Explanation:
The angular velocity of the minute hand is given by
T= time period of the minute hand=60 min=3600 s
so ω= 2 π/3600 rad/s
Now linear velocity v= r ω
r= radius of minute hand=14 cm
so v= 14 (2 π/3600)
V=0.0244 cm/s
The magnitude of the downward acceleration of the hollow cylinder is 6m/s^2.
Z = I α
T.R =1/2 M ( +
)α
T.R = 1/2M 5/4 α
T = 5Ma/8
Mg - T = Ma
Mg - 5Ma/8 = Ma
Mg= 5Ma/8 + Ma = 13Ma / 8
acceleration = 8g/13 = 6 m/s^2
The rate at which an object's velocity with respect to time changes is called its acceleration. The direction of the net force imposed on an item determines its acceleration in relation to that force. According to Newton's Second Law, the magnitude of an object's acceleration is the result of two factors working together
The size of the net balance of all external forces acting on that item is directly proportional to the magnitude of this net resultant force; the magnitude of that object's mass, depending on the materials from which it is built, is inversely related to its mass.
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