Answer:
hydrogen + oxygen = water
Answer:
Tigers and lions able to mate to produce cubs,but those cubs would not be able to go on to produce any off spring because their sex chromosomes do not match.
Explanation:
- Tigers and lions mate to produce ligers and tilons but they do not produce viable sperms or egg.
- In an organism there are two copies of chromosomes present in the somatic cells.
- But in case of sex cells they receive each set from mother and father. which they duplicate and divide during formation of gametes via meiosis.
- in such case if the sets are recieved from two different species then after pairing a mismatch will occur in the gene loci.For example, a eye colour gene may correspond to a paw length gene.
- Thus the gametes when produced will not be viable.
Answer:
Sp3
Explanation:
Hydrocarbon can be defined as an organic compound that comprises of hydrogen and carbon only. Some examples of hydrocarbon are methane, butane, ethane, ethene, etc.
Hybridization can be defined as a phenomenon which involves the combination of two or more atomic orbitals to form the same number of hybrid orbitals, with each of the orbitals having the same shape and energy.
In Organic chemistry, ethane is considered to be a tetrahedral carbon and it's Sp3 hybridized.
A tetrahedral carbon typically comprises of four bonds that are 109. 5° apart while a linear carbon atom comprises of two (2) bonds that are 180° apart.
Hence, the molecule of ethane posses a Sp3 hybridization because it has four bonds arrange with a tetrahedral geometry.
Answer:
Explanation:
Given parameters :
Volume of solution = 100mL
Absorbance of solution = 0.30
Unknown:
Concentration of CuSO₄ in the solution = ?
Solution:
There is relationship between the absorbance and concentration of a solution. They are directly proportional to one another.
A graph of absorbance against concentration gives a value of 0.15M at an absorbance of 0.30.
The concentration is 0.15M
Also, we can use: Beer-Lambert's law;
A = ε mC l
where εm is the molar extinction coefficient
C is the concentration
l is the path length
Since the εm is not given and assuming path length is 1;
Then we solve for the concentration.
