Explanation:
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<span>Let's make a few assumptions.
1. The paratrooper's lowest speed will be just prior to impact.
2. Since the jump was from a relatively low altitude, the paratrooper used a static line and the parachute should have opened almost immediately upon jumping.
So let's convert 100 mi/h to ft/s
100 mi/h * 5280 ft/mi / 3600 s/h = 146.67 ft/sec
Given the 1st assumption above, the MAXIMUM distance the paratrooper would have fallen would be 8 seconds at 146.67 ft/s, so
8 s * 146.67 ft/s = 1173.36 ft
The calculated distance is close to the jump distance, which agrees with both assumptions 1 and 2. So this account does seem reasonable.
Additionally, looking for the speed of a parachutist doing a freefall in the belly-to-earth position with arms and legs outspread, they will generally reach a terminal velocity of 120 mi/h which is slightly faster than the 100 mi/h in the article. This too is in agreement with the defective parachute flapping and causing some extra air resistance.</span>
Answer:
v(7) = 52.915 m/s
Explanation:
First, find the value for acceleration.
F = ma
100 = .5 * a
a = 200 m/s²
Next find the velocity at x = 7 using kinematic equations.
v² = v₀² + 2a(Δx)
v² = (0)² + 2(200)(7)
v = 
v = 52.915 m/s
Answer:
Strong nuclear force
Explanation:
Strong nuclear force (which is the strongest of the forces of the universe) is responsible for the attractive force between quarks to form nucleons (protons and neutrons). It is the reason why the protons (that are positive in charge) do not fly apart due to electromagnetic repulsion in the nucleus of an atom.
