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Rufina [12.5K]
2 years ago
9

A mutation in a certain type of bees allows for bees to pollinate only one type of flour how could this mutation be both a benef

it and risk to the organisms justify your response into or more complete sentences
Chemistry
1 answer:
Alina [70]2 years ago
3 0
It will benefit the flower because it will always get Polonated but it can be bad for the bees because if the flower dies so will the bees
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What is an organ that produces enzymes that break down nutrients
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The pancreas, it produces a juice that contains several enzymes that breaks down nutrients.
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3 years ago
How many chlorine atoms are found in 8.3 moles of chlorine?
erik [133]

Answer:

5*10²⁴ chlorine atoms are found in 8.3 moles of chlorine.

Explanation:

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number represents a quantity without an associated physical dimension, so it is considered a pure number that allows describing a physical characteristic without an explicit dimension or unit of expression. Avogadro's number applies to any substance.

Then you can apply the following rule of three: if 1 mole of the compound contains 6.023 * 10²³ atoms, 8.3 moles of the compound how many atoms does it have?

amount of atoms=\frac{8.3 moles*6.023*10^{23}atoms }{1 mole}

amount of atoms≅ 5*10²⁴ atoms

<u><em>5*10²⁴ chlorine atoms are found in 8.3 moles of chlorine.</em></u>

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2 years ago
I need helpppp plzzzz
Inessa [10]

Answer:

at first i would like to tell which class

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125000 is the answwr

8 0
3 years ago
If you want to prepare 80.0 mL of 4.00M acid ,How many mL of 12.4 M HCl are required ?
Oksi-84 [34.3K]

M_{A}V_{A}=M_{B}V_{B}\\(80.0)(4.00)=V_{B}(12.4)\\V_{B}=\frac{(80.0)(4.00)}{12.4} \approx \boxed{25.8 \text{ mL}}

5 0
1 year ago
What percentage of radioactive substance remains after two half-lives
Ksju [112]

Answer:

After 2 half-lives there will be 25% of the original isotope, and 75% of the decay product. After 3 half-lives there will be 12.5% of the original isotope, and 87.5% of the decay product. After 4 half-lives there will be 6.25% of the original isotope, and 93.75% of the decay product.

Explanation:

3 0
2 years ago
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