The correct option is ALL CHOICES
Conformity is defined as compliance with standard laws, that is, behaving in a manner that is in accordance with what is expected of the community or the society in which one lives. Conformity is expected of every one that lives in a community but this may not be an appropriate thing to do under some circumstances. In a situation in which one's conformity will make one to behave rudely, carry out illegal actions or be involved in unethical actions, such conformity should be ignored.
There are several things wrong with the question:
-- " 5 m/s " is not a turning speed.
-- 'Constant speed' can mean zero acceleration, or it can mean
huge acceleration if it's constant speed around a circle. There's
not enough information here to tell the difference.
-- The answer to an "is it ?" question is 'yes' or 'no', not 'true' or 'false'.
All in all, this question is so ragged that any reliable answer
should probably be as negative as possible.
Answer:
A = g (λ / 2π)² μ / Ts
Explanation:
The ant becomes "weightless" when its acceleration is equal to gravity. The motion of the ant is a sinusoidal wave:
y = A sin(ωt)
By taking the derivative twice, we can find the acceleration of the ant:
y' = Aω cos(ωt)
y" = -Aω² sin(ωt)
The maximum acceleration occurs when sine is 1. We want this to happen at a = -g.
-g = -Aω² (1)
A = g / ω²
Angular frequency is 2π times the normal frequency:
ω = 2πf
A = g / (2πf)²
Frequency is velocity divided by wavelength:
f = v / λ
A = g / (2πv / λ)²
A = g (λ / 2π)² / v²
Velocity of a wave in a string with tension Ts and linear density μ is:
v = √(Ts / μ)
Therefore:
v² = Ts / μ
Plugging in:
A = g (λ / 2π)² / (Ts / μ)
A = g (λ / 2π)² μ / Ts
An object in equilibrium has no NET force acting on it. It's acceleration is zero, meaning that it's moving in a straight line with constant speed (which may be zero).
Acoustics is the interdisciplinary science that deals with the study of mechanical waves in gases, liquids, and solids including vibration, sound, ultrasound, and infrasound. Cheers.
