Answer:
there needs to be a picture to answer
13 protons = Aluminum
13+14 = 27
<u><em>
Aluminum-27</em></u>
Answer:
The answer to your question is letter A. 2
Explanation:
Data
Octane = C₈H₁₈
Oxygen = O₂
Carbon dioxide = CO₂
Water = H₂O
Reaction
C₈H₁₈ + O₂ ⇒ CO₂ + H₂O
Reactants Elements Products
8 C 1
18 H 2
2 O 3
This reaction is unbalanced
C₈H₁₈ + 25/2O₂ ⇒ 8CO₂ + 9H₂O
Reactants Elements Products
8 C 8
18 H 18
25 O 25
Multiply the reaction by 2
2C₈H₁₈ + 25O₂ ⇒ 16CO₂ + 18H₂O
Reactants Elements Products
16 C 16
36 H 36
50 O 50
Now, the reaction is balanced
When the value of Ksp = 3.83 x 10^-11 (should be given - missing in your Q)
So, according to the balanced equation of the reaction:
and by using ICE table:
Ag2CrO4(s) → 2Ag+ (Aq) + CrO4^2-(aq)
initial 0 0
change +2X +X
Equ 2X X
∴ Ksp = [Ag+]^2[CrO42-]
so by substitution:
∴ 3.83 x 10^-11 = (2X)^2* X
3.83 x 10^-11 = 4 X^3
∴X = 2.1 x 10^-4
∴[CrO42-] = X = 2.1 x 10^-4 M
[Ag+] = 2X = 2 * (2.1 x 10^-4)
= 4.2 x 10^-4 M
when we comparing with the actual concentration of [Ag+] and [CrO42-]
when moles Ag+ = molarity * volume
= 0.004 m * 0.005L
= 2 x 10^-5 moles
[Ag+] = moles / total volume
= 2 x 10^-5 / 0.01L
= 0.002 M
moles CrO42- = molarity * volume
= 0.0024 m * 0.005 L
= 1.2 x 10^-5 mol
∴[CrO42-] = moles / total volume
= (1.2 x 10^-5)mol / 0.01 L
= 0.0012 M
by comparing this values with the max concentration that is saturation in the solution
and when the 2 values of ions concentration are >>> than the max values o the concentrations that are will be saturated.
∴ the excess will precipitate out