Light-colored clothing reflects light and dark-colored clothing absorbs it
<span>0.967 x 10^-6 HZ
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The question is incomplete, here is the complete question:
The given chemical equation follows:

What is the equilibrium constant expression for the given system?
<u>Answer:</u> The expression of equilibrium constant for the given equation is ![K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BH_2%5D%5E2%5BO_2%5D%7D%7B%5BH_2O%5D%5E2%7D)
<u>Explanation:</u>
Equilibrium constant is the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as 
For a general chemical reaction:

The expression for
is written as:
![K_{eq}=\frac{[C]^c[D]^d}{[A]^a[B]^b}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BC%5D%5Ec%5BD%5D%5Ed%7D%7B%5BA%5D%5Ea%5BB%5D%5Eb%7D)
The given chemical equation follows:

The expression for
for above equation follows:
![K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BH_2%5D%5E2%5BO_2%5D%7D%7B%5BH_2O%5D%5E2%7D)
Hence, the expression of equilibrium constant for the given equation is ![K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BH_2%5D%5E2%5BO_2%5D%7D%7B%5BH_2O%5D%5E2%7D)
Answer:
a.
![K=\frac{[BaO]^2}{[Ba]^2[O_2]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BBaO%5D%5E2%7D%7B%5BBa%5D%5E2%5BO_2%5D%7D)
b.
![K=\frac{[MgO]^2}{[Mg]^2[O_2]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BMgO%5D%5E2%7D%7B%5BMg%5D%5E2%5BO_2%5D%7D)
c.
![K=\frac{[P_4O_{10}]^2}{[P_4][O_2]^5}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BP_4O_%7B10%7D%5D%5E2%7D%7B%5BP_4%5D%5BO_2%5D%5E5%7D)
Explanation:
Hello!
In this case, since the equilibrium expression is set up by dividing the products over the reactants and powering to the stoichiometric coefficient, we can proceed as follows:
a. 2 Ba + O2 ⇌ 2 BaO.
![K=\frac{[BaO]^2}{[Ba]^2[O_2]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BBaO%5D%5E2%7D%7B%5BBa%5D%5E2%5BO_2%5D%7D)
b. 2 Mg + O2 ⇌ 2MgO
![K=\frac{[MgO]^2}{[Mg]^2[O_2]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BMgO%5D%5E2%7D%7B%5BMg%5D%5E2%5BO_2%5D%7D)
c. P4 + 5 O2 ⇌ P4O10
![K=\frac{[P_4O_{10}]^2}{[P_4][O_2]^5}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BP_4O_%7B10%7D%5D%5E2%7D%7B%5BP_4%5D%5BO_2%5D%5E5%7D)
Best regards.
The answer is a because it's electron configuration is ns1