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Irina-Kira [14]
3 years ago
9

Predict the effect of adding a non competitive inhibitor to the reaction mixture on the rate of reaction at a high substrate con

centration. Support your prediction by describing how a non competitive inhibitor affects the structure and function of an enzyme.
Chemistry
1 answer:
Darya [45]3 years ago
8 0

Answer:

A noncompetitive inhibitor can only bind to an enzyme with or without a substrate at several places at a particular point in time

Explanation:

this is because It changes the conformation of an enzyme as well as its active site, which makes the substrate unable to bind to the enzyme effectively so that the efficiency of the enzyme decreases. A noncompetitive inhibitor binds to the enzyme away from the active site, altering/distorting the shape of the enzyme so that even if the substrate can bind, the active site functions less effectively and most of the time also the inhibitor is reversible

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Answer:

See explanation

Explanation:

The magnitude of electronegativity difference between atoms in a bond determines whether that bond will be polar or not.

If the electronegativity difference between atoms in a bond is about 1.7, the bond is ionic. If the electronegativity difference is greater than 0.4 and less than 1.7, the bond will have a polar covalent character. Lastly, if the electronegativity difference between the bond is less than or equal to 0.4, the covalent bond is non polar.

The electronegativity difference between carbon and hydrogen is about 0.4 which corresponds to a nonpolar covalent bond hence the molecule is nonpolar.

The electronegativity difference between carbon and fluorine is about 1.5 indicating a highly polar bond. This gives CH3F an overall dipole moment thereby making the molecule polar.

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3 years ago
Flammable materials, like alcohol, should never be
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Answer:

b.open flame because it is fundamental end of the alcohol mixes in with the flame then it will become a bigger fire

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Ba2+(aq)+SO42−(aq)→BaSO4(s)
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4 0
3 years ago
What is the volume, in liters, of 1.40 mol of oxygen gas at 20.0°C and 0.974 atm?
topjm [15]

Answer:

V = 34.55 L

Explanation:

Given that,

No of moles, n = 1.4

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We need to find the volume of the gas. It can be calculated using Ideal gas equation which is :

PV=nRT

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Finding for V,

V=\dfrac{nRT}{P}\\\\V=\dfrac{1.4\times 0.08206\times 293}{0.974 }\\\\V=34.55\ L

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Which chemical reaction needs more energy to break bonds in the reactants
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3 years ago
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