When PH = -㏒[H3O+]
and we have PH = 5.061
by substitution:
∴ [ H3O+] = 10^-5.061 = 8.7x10^-6
when we have Ka = [CH3COO-][H3O+] / [CH3COOH]
we have Ka = 1.8x10^-5 & [H3O+] = 8.7x10^-6m & [CH3COOH] = 0.5 m
by substitution in Ka formula:
1.8x10^-5 = [CH3COO-]*(8.7x10^-6) / 0.5
∴[CH3COO-] = 1.034
∴we need to add 1.034 mol of sodium acetate
Given the parent compound, draw the mass spectrum fragment that is observed at m/z 77. Include any hydrogen atoms and the charge. Its 6 carbon ring with 3 double bonds and a Cl coming off the of it.
It should be Carbon Nanotubes
Answer:
the answer is the second option
