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denis23 [38]
3 years ago
6

A molecule of common table salt, or nacl, is the result of _____ bond forming between a sodium (na) atom and a chlorine (cl) ato

m.
Chemistry
1 answer:
jekas [21]3 years ago
4 0
I believe the correct term to fill in the blank would be ionic. A molecule of common table salt, or nacl, is the result of ionic bond forming between a sodium (na) atom and a chlorine (cl) atom. Ionic bonding is a result of complete transfer of electrons between atoms. It usually happens between a metal and a nonmetal.
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Rubidium will react with oxygen in which of the following formulas?
dusya [7]

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Explanation:

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What is the percent by mass of water in Na2SO4 • 10H2O?
bulgar [2K]
We determine the percent by mass of water in the compound by dividing the mass of  water by the total mass. The total mass of Na2SO4.10H2O is equal to 322 g. The mass of water is 180 g. 
       
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4 years ago
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Be sure to answer all parts. Consider the reaction N2(g) + 3H2(g) → 2NH3(g)ΔH o rxn = −92.6 kJ/mol If 4.0 moles of N2 react with
Sphinxa [80]

Answer : The work done is, 1.98\times 10^4J

Explanation :

The given balanced chemical reaction is:

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

When 4 moles of N_2 react with 12 moles of H_2 then it gives 8 moles of NH_3

First we have to calculate the change in moles of gas.

Moles on reactant side = Moles of N_2 + Moles of H_2

Moles on reactant side = 4 + 12 = 16 moles

Moles on product side = Moles of NH_3

Moles on reactant side = 8 moles

Change in moles of gas = 16 - 8 = 8 moles

Now we have to calculate the change in volume of gas.

Using ideal gas equation:

PV=nRT

where,

P = Pressure of gas = 1.0 atm

V = Volume of gas = ?

n = number of moles of gas = 8 mole

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of gas = 25^oC=273+25=298K

Putting values in above equation, we get:

1.0atm\times V=8mole\times (0.0821L.atm/mol.K)\times 298K

V=195.7L

As the number of moles of gas decreased. So, the volume also deceased. Thus, the volume of gas will be, -195.7 L

Now we have to calculate the work done.

Formula used :

w=-p\Delta V

where,

w = work done

p = pressure of the gas = 1.0 atm

\Delta V = change in volume = -195.7 L

Now put all the given values in the above formula, we get:

w=-p\Delta V

w=-(1.0atm)\times (-195.7L)

w=195.7L.artm=195.7\times 101.3J=19824.41J=1.98\times 10^4J

conversion used : (1 L.atm = 101.3 J)

Thus, the work done is, 1.98\times 10^4J

6 0
3 years ago
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