Answer:
I don't know what the hell is going on with the this.
1L=1000 mL,L GOES BOTTOM AND mL GOES TOP,ANSWER SHOULD BE 42700.
Answer:
900 J/mol
Explanation:
Data provided:
Enthalpy of the pure liquid at 75° C = 100 J/mol
Enthalpy of the pure vapor at 75° C = 1000 J/mol
Now,
the heat of vaporization is the the change in enthalpy from the liquid state to the vapor stage.
Thus, mathematically,
The heat of vaporization at 75° C
= Enthalpy of the pure vapor at 75° C - Enthalpy of the pure liquid at 75° C
on substituting the values, we get
The heat of vaporization at 75° C = 1000 J/mol - 100 J/mol
or
The heat of vaporization at 75° C = 900 J/mol
PH of a solution is -ln[H3O+]
so,in case of A pH=3 or,-log[H3O+]=3 or,[H3O+]=10^-3
in case of B pH=6 pr,-log[H3O+]=6 or, [H3O+]=10^-6
so,hydronium ion concentration in solution A /the hydronium ion concentration in solution Z
=10^-3/10^-6
=1000
2)
Ca(OH)2+2 HNO3=Ca(NO3)2+2 H2O
so the answer is 2.
