A single paragraph can be selected by triple in the paragraph. ture or false

3. An astronaut on a space-walk swings a 0.5 kg metal tool in a circular path at the end of a cable 3.6 m long. The astronaut th

Semenov [28]

Answer:

Explanation:

2 km a hour

6 0

3 years ago

Flapping flight is very energy intensive. A wind tunnel test

steposvetlana [31]

Answer:

The metabolic power for starting flight=134.8W/kg

Explanation:

We are given that

Mass of starling, m=89 g=89/1000=0.089 kg

1 kg=1000 g

Power, P=12 W

Speed, v=11 m/s

We have to find the metabolic power for starting flight.

We know that

Metabolic power for starting flight= $\frac{P}{m}$

Using the formula

Metabolic power for starting flight= $\frac{12}{0.089}$

Metabolic power for starting flight=134.8W/kg

Hence, the metabolic power for starting flight=134.8W/kg

4 0

3 years ago

Okay i'm totally stuck and nobody I know really gets it either, so i've turned to Yahoo for help :)

OlgaM077 [116]

Here is the rule for see-saws here on Earth, and there is no reason
to expect that it doesn't work exactly the same anywhere else:

 (weight) x (distance from the pivot) on one side
is equal to
 (weight) x (distance from the pivot) on the other side.

That's why, when Dad and Tiny Tommy get on the see-saw, Dad sits
closer to the pivot and Tiny Tommy sits farther away from it.

 (Dad's weight) x (short length) = (Tiny Tommy's weight) x (longer length).

So now we come to the strange beings on the alien planet.
There are three choices right away that both work:

#1).
(400 N) in the middle-seat, facing (200 N) in the end-seat.

 (400) x (1) = (200) x (2)

#2).
(200 N) in the middle-seat, facing (100 N) in the end-seat.

 (200) x (1) = (100) x (2)

#3).

On one side: (300 N) in the end-seat (300) x (2) = 600

On the other side:
 (400 N) in the middle-seat (400) x (1) = 400
 and (100 N) in the end-seat (100) x (2) = 200
Total . . . . . . . . . . . . 600

These are the only ones to be identified at Harvard . . . . . . .
There may be many others but they haven't been discarvard.

5 0

3 years ago

Read 2 more answers

A 24 cm radius aluminum ball is immersed in water. Calculate the thrust you suffer and the force. Knowing that the density of al

Illusion [34]

Answer:

W =1562.53 N

Explanation:

It is given that,

Radius of the aluminium ball, r = 24 cm = 0.24 m

The density of Aluminium, $d=2698.4\ kg/m^3$

We need to find the thrust and the force. The mass of the liquid displaced is given by :

$m=dV$

V is volume

Weight of the displaced liquid

W = mg

$W=dVg$

So,

$W=dg\times \dfrac{4}{3}\pi r^3\\\\W=2698.4\times 10\times \dfrac{4}{3}\times \pi \times (0.24)^3\\\\W=1562.53\ N$

So, the thrust and the force is 1562.53 N.

7 0

2 years ago

A 1.00 -kg object slides to the right on a surface having a coefficient of kinetic friction 0.250 (Fig. P8.62a). The object has

LekaFEV [45]

The distance D where the object comes to rest is 1.08.m.

<h3>What is the distance?</h3>

The separation of one thing from another in space; the distance or separation in space between two objects, points, lines, etc.; remoteness. The distance of seven miles cannot be accomplished in one hour of walking.
Learn how to use the Pythagorean theorem to get the separation between two points using the distance formula. The Pythagorean theorem can be rewritten as d==(((x 2-x 1)2+(y 2-y 1)2)
The distance between any two places is the length of the line segment separating them. By measuring the length of the line segment that connects the two points in coordinate geometry, the distance between them may be calculated.

(c) the distance D where the object comes to rest.

$W_{total} =$ ΔKE ⇒ -0.25*1*9.8*D = 0-1/2*1* $2.3^{2}$

⇒ $D=\frac{0.5*2.3^{2} }{2.45}$

⇒1.08.m

To learn more about distance, refer to:

brainly.com/question/4998732

#SPJ4

5 0

1 year ago

A single paragraph can be selected by triple in the paragraph. ture or false​

A single paragraph can be selected by triple in the paragraph. ture or false