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Maslowich
3 years ago
13

Which of the following most likely happens during a physical change?

Chemistry
2 answers:
Paha777 [63]3 years ago
6 0

Answer:

B)Substance changes its form but not its molecular composition.

Explanation:

took the test

alexandr1967 [171]3 years ago
4 0

The correct answer is B.

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Ethane is an alkane having two carbon atoms bound to hydrogen atoms. Recall what you have learned about the tetravalent nature o
svlad2 [7]
The molecule for ethane is C2H6. or CH3-CH3. 

Carbon LOVES hydrogen. If possible, Carbon would have four bonds attach to hydrogens. IN this molecule, one of the bond is used to attach a carbon to another carbon, so instead of 4 hydrogens, each carbon would have 3 hydrogens..
3 0
3 years ago
8. Write the formulas for and give the names of
kobusy [5.1K]
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6 0
2 years ago
If 3.289 x 10^23 atoms of potassium react with excess water, how many grams of hydrogen gas would be produced?
GarryVolchara [31]

Answer:

The amount in grams of hydrogen gas produced is 0.551 grams

Explanation:

The parameters given are;

Number of atoms of potassium, aₙ = 3.289 × 10²³ atoms

Chemical equation for the reaction is given as follows;

2K + 2H₂O \rightarrow KOH + H₂

Avogadro's number, N_A, regarding the number of molecules or atom per mole is given s follows;

N_A = 6.02 × 10²³ atoms/mole

Therefore;

The number of moles of potassium present = 3.289 × 10²³/(6.02 × 10²³) = 0.546 moles

2 moles of potassium produces one mole of hydrogen gas, therefore;

1 moles of potassium produces 1/2 mole of hydrogen gas, and 0.546 moles of potassium will produce 0.546/2 moles of hydrogen which is 0.273 moles of hydrogen gas

The molar mass of hydrogen gas = 2.016 grams

Therefore, 0.273 moles will have a mass of 0.273×2.016 = 0.551 grams.

The amount in grams of hydrogen gas produced = 0.551 grams.

8 0
3 years ago
Can someone help pls
zysi [14]
What is the problem u need help with
3 0
2 years ago
A sample of gas X occupies 10 mº at a pressure of 120 kPa.
Mashutka [201]

Answer:

The new pressure of the gas comes out to be 400 KPa.

Explanation:

Initial volume of gas = V = 10\textrm{ m}^{3}

Initial pressure of gas = P = 120 KPa

Final volume of gas = V' = 3\textrm{ m}^{3}

Assuming temperature to be kept constant.

Assuming final pressure of the gas to be P' KPa

PV = P'V' \\120\textrm{ KPa}\times 10\textrm{ m}^{3} = \textrm{P'}\times 3\textrm{ m}^{3} \\\textrm{P'} = 400\textrm{ KPa}

New pressure of gas = 400 KPa

5 0
2 years ago
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