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Svetllana [295]
3 years ago
12

A fisherman notices that his boat is moving up and down periodically without any horizontal motion, owing to waves on the surfac

e of the water. It takes a time of 2.30 ss for the boat to travel from its highest point to its lowest, a total distance of 0.650 mm. The fisherman sees that the wave crests are spaced a horizontal distance of 6.10 mm apart.
(a) How much is the wavelength? Express your answer using three significant figures.
(b) Find the period of the wave. Express your answer using three significant figures.
(c) How fast are the waves traveling? Express the speed v in meters per second using three significant figures.
(d) What is the amplitude A of each wave? Express your answer in meters using three significant figures.
Physics
1 answer:
matrenka [14]3 years ago
6 0

Answer:

a) 6.1 m

b) 4.6 s

c) 1.326 m/s

d) 0.325 m

Explanation:

a) The wave length is the distance between 2 crests λ = 6.1m

b) The period of the wave is the time it takes from the lowest point to the next lowest point, which is twice the time it takes from the lowest point to the highest point = 2*2.3 = 4.6 s

c) The speed of the wave is the distance per unit of time, or wave length over period = 6.1 / 4.6 = 1.326 m/s

d)The amplitude A is half the distance from the highest point to the lowest point = 0.65 / 2 = 0.325 m

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It is a battery (the long and short lines represent 2 cells)
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Light is incident on an air-water interface at an angle of 30 degree to the normal. What angle does the refracted ray make with
Vikentia [17]

Answer:

22 degree

Explanation:

Angle of incidence, i = 30 degree

the refractive index of water with respect to air is 4/3.

As the ray of light travels from rarer medium to denser medium, that mean air to water, the refraction takes place.

According to Snell's law,

Refractive index of water with respect to air = Sin i / Sin r

Where, r be the angle of refraction

4 / 3 = Sin 30 / Sin r

0.75 = 2 Sin r

Sin r = 0.375

r = 22 degree

Thus, the angle of refraction is 22 degree.

6 0
3 years ago
An object has a weight of 500 on earth what is the mass of this object
erastova [34]

550! OBVY! lol! ope this helps1

7 0
3 years ago
A person's body is producing energy internally due to metabolic processes. If the body loses more energy than metabolic processe
SVETLANKA909090 [29]

Answer:

T_s = 6.8 degree C

Explanation:

As per thermal radiation we know that rate is heat radiation is given as

\frac{dQ}{dt} = \sigma eA (T^4 - T_s^4)

here we know that

T = 34 degree C = 307 K

A = 1.38 m^2

e = 0.557

\sigma = 5.67 \times 10^{-8} W/m^2K^4

\frac{dQ}{dt} = 120 J/s

now we have

120 = (5.67 \times 10^{-8})(0.557)(1.38)(307^4 - T_s^4)

120 = (4.36 \times 10^{-8})(307^4 - T_s^4)

T_s = 279.8 K

T_s = 6.8 degree C

5 0
3 years ago
A woman walked 115 m. As she did so, her speed increased from 4.20 m/s to 5.00 m/s. How long did it take her to walk this distan
ASHA 777 [7]

Answer:

25 seconds

Explanation:

Assuming the woman is accelerating at a constant rate of a \;\;m/s^2 from the initial velocity, u=4.20 m/s, to the final velocity, v=5.00 m/s.

Let she takes t seconds to cover the distance, s=115 m.

As acceleration, a=\frac{v-u}{t}=\frac{5-4.2}{t}

\Rightarrow at=0.8\cdots(i)

Now, from the equation of motion

s=ut+\frac 12 at^2

\Rightarrow s=ut+\frac 12 at(t)

\Rightarrow 115=4.2t+\frac 12 \times 0.8 t [ from equation (i)]

\Rightarrow 115=(4.2+0.4)t

\Rightarrow t= 115/4.6 = 25 seconds.

Hence, she takes 25 seconds to walk the distance.

5 0
3 years ago
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