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2 years ago

PLZZZZZ HELPPP I NEED A 5 ESSAY ON HOW THE BODY WORKS. JKKKKK!!!! FREE POINTS!FIRST TO REPLY GETS BRANLIEST

Chemistry

2 answers:

Y_Kistochka [10]2 years ago

8 0

Answer:

lol thx

Explanation:

bezimeni [28]2 years ago

6 0

Answer:

hhhahahaha

Explanation:

lol

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Please help with question 4 and 5 please!!

ratelena [41]

Question four is : Gaseous state

Question five is : A rise in temperature increases the kinetic energy and speed of particles; it does not weaken the forces between them. The particles in solids vibrate about fixed positions; even at very low temperatures. Individual particles in liquids and gases have no fixed positions and move chaotically.

Hope this helps!

Have a great day!

8 0

3 years ago

Which planet formed near the sub where the solar system l’s temperatures were very high

Harrizon [31]

Answer:

Mars

Explanation:

Terrestrial or inner planets like Mars and Venus were formed near the Sun where the solar system's temperatures were very high.

4 0

3 years ago

Read 2 more answers

If you exhale 7.25×10 to the 24th power molecules of CO2. How many moles of CO3 do you exhale?

Assoli18 [71]

None since CO3 does not exist.

7 0

3 years ago

Gases are measured in different units. Which of the following measurements of pressure are equal? Select all that apply.

viva [34]

Explanation:

Pressure of a gas is the combined force with which the molecules bombard a unit area of the wall of the container.

1 atm = 760mmHg

= 760torr

= 101325Pa

= 101325Nm⁻²

1mmHg = 1torr

1Pa = 1Nm⁻²

101.325 kPa and 101,325 Pa are the same

1000Pa = 1kPa

101,325 Pa and 1 atm

1atm and 101.325 kPa

6 0

2 years ago

what is the percent yield of titanium (II) oxide if 20.0 grams of titanium (II) sulfide is reacted with water? The actual yield

earnstyle [38]

Answer : The percent yield of titanium (II) oxide is, 142.5 % and the impurities could have caused the percent yield to be so high.

Explanation : Given,

Mass of titanium(II) sulfide = 20.0 g

Molar mass of titanium(II) sulfide = 79.9 g/mole

Molar mass of titanium(II) oxide = 63.9 g/mole

First we have to calculate the moles of titanium(II) sulfide.

$\text{ Moles of titanium(II) sulfide}=\frac{\text{ Mass of titanium(II) sulfide}}{\text{ Molar mass of titanium(II) sulfide}}=\frac{20.0g}{79.9g/mole}=0.2503moles$

Now we have to calculate the moles of titanium(II) oxide.

The balanced chemical reaction is,

$TiS+H_2O\rightarrow TiO+H_2S$

From the reaction, we conclude that

As, 1 mole of titanium(II) sulfide react to give 1 mole of titanium(II) oxide

So, 0.2503 mole of titanium(II) sulfide react to give 0.2503 mole of titanium(II) oxide

Now we have to calculate the mass of titanium(II) oxide.

$\text{ Mass of titanium(II) oxide}=\text{ Moles of titanium(II) oxide}\times \text{ Molar mass of titanium(II) oxide}$

$\text{ Mass of titanium(II) oxide}=(0.2503moles)\times (63.9g/mole)=15.99g$

To calculate the percentage yield of titanium (II) oxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of titanium (II) oxide = 22.8 g

Theoretical yield of titanium (II) oxide = 15.99 g

Putting values in above equation, we get:

$\%\text{ yield of titanium (II) oxide}=\frac{22.8g}{15.99g}\times 100\\\\\% \text{yield of titanium (II) oxide}=142.5\%$

Hence, the percent yield of titanium (II) oxide is, 142.5 %

If the percent yields is greater than 100% that means the product of the reaction contains impurities which cause its mass to be greater than it actually.

5 0

3 years ago