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sammy [17]
3 years ago
14

PLZZZZZ HELPPP I NEED A 5 ESSAY ON HOW THE BODY WORKS. JKKKKK!!!! FREE POINTS!FIRST TO REPLY GETS BRANLIEST

Chemistry
2 answers:
Y_Kistochka [10]3 years ago
8 0

Answer:

lol thx

Explanation:

bezimeni [28]3 years ago
6 0

Answer:

hhhahahaha

Explanation:

lol

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HELP ME PLSSSSS THIS TEST IS TIMED!!!! Write a conclusion statement that addresses the following questions: • How did your exper
SVETLANKA909090 [29]

Although the data for the experiment was not provided, we can offer a generalized answer in that when performing an experiment to achieve absolute zero temperatures, the value will never match the exact value.

<h3 /><h3>What is absolute zero?</h3>

Absolute zero is the lower limit of temperature. It is considered the coldest possible temperature that can exist. However, any attempt to reach this temperature in a controlled environment has failed, <u>scientists do not think it is possible to recreate this </u><u>temperature</u><u>. </u>

Therefore, we can confirm that the value of the absolute zero experiments did not match the accepted value. If the hypothesis was that it would be difficult or impossible to achieve, then the data would support the hypothesis, otherwise, it would fail to do so.

In summary, absolute zero is a temperature that cannot be recreated in a lab, so the value in this experiment does not match the accepted value and there is <u>no further exploration </u>to be done on this matter.

To learn more about absolute zero visit:

brainly.com/question/79835?referrer=searchResults

4 0
2 years ago
Thallium consists of 29.5%TI-203 and 70.5%TI-205. What is the relative atomic mass of thallium
Galina-37 [17]
To determine the relative atomic mass of thallium, we multiply the molar mass of the isotopes to their corresponding relative abundance. The molecular percentages should sum up to 1. In this case, we multiply 203 by 0.295 and 205 by 0.705 and add the answers of the two. The final atomic mass is 204.41 g/mol.
3 0
3 years ago
What is the empirical formula for the following molecular formula: C10H5O2
Tju [1.3M]

The empirical formula is the same as the molecular formula : C₁₀H₅O₂

<h3>Further explanation</h3>

Given

Molecular formula : C₁₀H₅O₂

Required

The empirical formula

Solution

The empirical formula (EF) is the smallest comparison of atoms of compound forming elements.  

The molecular formula (MF) is a formula that shows the number of atomic elements that make up a compound.  

(empirical formula) n = molecular formula  

<em>(EF)n=MF </em>

(EF)n = C₁₀H₅O₂

If we divide by the number of moles of Oxygen (the smallest) which is 2 then the moles of Hydrogen will be a decimal number (not whole), which is 2.5, then the empirical formula is the same as the molecular formula

4 0
3 years ago
Explain answer too, CHEM HELP
mestny [16]
B and E are the answers I would choose.

On the left side, you have 2 nitrogen. On the right, you only have one. So put a 2 in front of the NH3. That gives you balanced nitrogen.

After that step, you have 6 hydrogen (the coefficient x the subscript) on the right, so you need to get 6 on the left. You have 2 hydrogen (subscript). 6/2 = 3, so put a coefficient of 3 in front of the H2, and you’ll have 6 hydrogen.

Your balanced equation is N2 + 3H2 -> 2NH3

Please lmk if you have questions.
5 0
3 years ago
what will the new volume of a 22.4L same of a gas at STP if the pressure remains constant and the temperature is cut in half? A.
In-s [12.5K]

Answer:

\boxed{\text{C. 11.2 L}}

Explanation:

The pressure is constant, so we can use Charles' Law to calculate the volume.

\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}

Data:

V₁ = 22.4 L; T₁ = 273.15 K

V₂ = ?;         T₂ = 136.58 K

Calculations:

\dfrac{ 22.4}{273.15} = \dfrac{ V_{2}}{136.58}\\\\0.082 00 = \dfrac{ V_{2}}{136.58}\\\\V_{2} =0.082 00 \times 136.58 = \boxed{\textbf{11.2 L}}

5 0
3 years ago
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