Question

A 6-column table with 1 row. The first column labeled Number of Washers has entry 2. The second column labeled initial velocity v subscript 1 (meters per second) has entry 0.13. The third column labeled final velocity v subscript 2 (meters per second) has entry 0.36. The fourth column labeled Time to travel 0.25 meters t subscript 1 (seconds) has entry 1.92. The fifth column labeled time to travel 0.5 meters t subscript 2 (seconds) has entry 2.61. The sixth column labeled Acceleration a = StartFraction (v subscript 2 minus v subscript 1) over (t subscript 2 minus t subscript 1) EndFraction (meters per second squared) has entry empty.
The acceleration of the car with the data in the table above would be
m/s2.

If the applied force were cut in half, what do you predict the acceleration would be?
m/s2

Answer 1

Answer:

The acceleration of the car with the data in the table above would be

0.33  m/s2.

If the applied force were cut in half, what do you predict the acceleration would be?

0.17  m/s2

Explanation:

Just did this problem! :)

Answer 2

Answer:

The acceleration of the car with the data in the table above would be

0.33  m/s^2

If the applied force were cut in half, what do you predict the acceleration would be?

0.17  m/s^2

Explanation:

i did the test, but if u do not believe me,

0.36-0.13= 0.23

2.61-1.92=0.69  

then 0.23/0.69= 0.3333333333333333333333333333333, which rounds to 0.33, according to the formula, a=(v2-v1)/(t2-t1)m/s^2, so you need to divide.

to find the second part, if you divide 0.33/2=0.175, which rounds to 0.17(its the answer its correct)