All categories

3 years ago

Water can break down rocks because

2 answers:

7 0

Rainwater fills small cracks in a rock. As the water freezes, it expands, widening the cracks and splitting apart the rock.

I would say this too.

HOPE THIS HELPS:)

4vir4ik [10]3 years ago

4 0

Ice wedging, pressure release, plant root growth, and abrasion can all break apartrocks. ... When plants grow in cracks in a rock, their roots can widen the cracks and force the rock apart. Rainwater fills small cracks in a rock. As the water freezes, it expands, widening the cracks and splitting apart the rock.

You might be interested in

How much heat is needed to melt 13.74 kg of silver that is initially at 20°C?

salantis [7]

Answer:

$Q = 4.63 \times 10^6 J$

Explanation:

As we know that melting point of silver is

T = 961.8 degree C

Latent heat of fusion of silver is given as

L = 111 kJ/kg

specific heat capacity of silver is given as

$s = 240 J/kg C$

now we will have

$Q = ms\Delta T + mL$

$\Delta T = 961.8 - 20$

$\Delta T = 941.8 degree C$

now from above equation

$Q = (13.74)(240)(941.8) + (13.74)(111 \times 10^3)$

$Q = 3.1 \times 10^6 + 1.53 \times 10^6$

$Q = 4.63 \times 10^6 J$

3 0

2 years ago

Racing greyhounds are capable of rounding corners at very high speeds. A typical greyhound track has turns that are 45 m diamete

Readme [11.4K]

Answer:

In m/s^2:

a=11.3778 m/s^2

In units of g:

a=1.161 g

Explanation:

Since the racing greyhounds are capable of rounding corners at very high speed so we are going use the following formula of acceleration for circular paths.

$a=\frac{v^2}{r}$

where:

v is the speed

r is the radius

Now,

$a=\frac{16^2}{45/2}\\ a=11.3778 m/s^2$

In g units:

$a=\frac{11.3778\ g}{9.8}\\ a=1.161\ g$

7 0

3 years ago

Ryan is driving home from work and notices a deer leaping onto the road about 25 m in front of his car. He immediately applies t

Anvisha [2.4K]

Answer:

mu = 0.56

Explanation:

The friction force is calculated by taking into account the deceleration of the car in 25m. This can be calculated by using the following formula:

$v^2=v_0^2+2ax\\$

v: final speed = 0m/s (the car stops)

v_o: initial speed in the interval of interest = 60km/h

= 60(1000m)/(3600s) = 16.66m/s

x: distance = 25m

BY doing a the subject of the formula and replace the values of v, v_o and x you obtain:

$a=\frac{v^2-v_o^2}{2x}=\frac{0m^2/s^2-(16.66m/s)^2}{2(25m)}=-5.55\frac{m}{s^2}$

with this value of a you calculate the friction force that makes this deceleration over the car. By using the Newton second's Law you obtain:

$F_f=ma=(1490kg)(5.55m/s^2)=8271.15N$

Furthermore, you use the relation between the friction force and the friction coefficient:

$F_f= \mu N=\mu mg\\\\\mu=\frac{F_f}{mg}=\frac{8271.15N}{(1490kg)(9.8m/s^2)}=0.56$

hence, the friction coefficient is 0.56

6 0

2 years ago

I will give brainliest to the best answer! I don’t understand vectors. This whole sheet is confusing me and i’m very behind, ple

Rudik [331]

Explanation:

1. To graphically add vectors, use the tail-to-tip method. Draw the first vector (it doesn't matter which), then draw the second vector where the first vector ends. The resultant vector is from the tail of the first vector to the tip of the second vector.

This graph shows two ways to get the resultant: A + B or B + A.

desmos.com/calculator/bqhcclhhqc

2. To algebraically add vectors, split each vector into x and y components.

Aₓ = 5.0 cos 45 = 3.5

Aᵧ = 5.0 sin 45 = 3.5

Bₓ = 2.0 cos 180 = -2.0

Bᵧ = 5.0 sin 180 = 0

The components of the resultant vector are the sums of the components of A and B.

Cₓ = 3.5 + -2.0 = 1.5

Cᵧ = 3.5 + 0 = 3.5

The magnitude of the resultant vector is found with Pythagorean theorem, and the direction is found with tangent.

C = √(Cₓ² + Cᵧ²) ≈ 3.9 m/s

θ = atan(Cᵧ / Cₓ) ≈ 67°

4 0

2 years ago

I need help with nine and 10 I will really appreciate it

horsena [70]

Answer:

9] V = D ÷ T

Take any distance value from the graph and its relevant time.

V = 4 ÷ 2

V = 2 m/s

[You will notice that any distance values with its time will give you 2 m/s as its speed. This means that speed is constant throughout.]

10] Take the distance value and its time for the highest peak of B.

V = 20 ÷ 2

V = 10 m/s

7 0

2 years ago