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Andreas93 [3]
3 years ago
9

The property that compares the mass of an object with its volume is _____.

Physics
2 answers:
Licemer1 [7]3 years ago
7 0
The property that compares the mass of an object with its volume is density.
Alja [10]3 years ago
6 0
The answer is density
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I need help please I will give points
stira [4]

Answer:

-5 N of force

Explanation:

Hope it helps!

3 0
3 years ago
What is a type of matter made up of a combination of elements
myrzilka [38]
A type of matter made up of a combination of elements is called a compound. for example table salt, is made up of two elements that by themselves are lethal but chemically combined cancel each other out there for becoming edible.
7 0
3 years ago
The density of nuclear matter is about 1018 kg/m3. Given that 1 mL is equal in volume to 1 cm3, what is the density of nuclear m
Sonbull [250]

Answer:

density is 10^{6} Mg/µL

Explanation:

given data

density of nuclear = 10^{18} kg/m³

1 ml = 1 cm³

to find out

density of nuclear matter in Mg/µL

solution

we know here

1 Mg = 1000 kg

so

1 m³ is equal to 10^{6} cm³

and here 1 cm³ is equal to  1 mL

so we can say 1 mL is equal to 10³ µL

so by these we can convert density

density = 10^{18} kg/m³

density = 10^{18} kg/m³ × \frac{10^{-3} }{10^{6} }  Mg/µL

density =  10^{6} Mg/µL

8 0
3 years ago
Read 2 more answers
400 N of load can be overcome by an effort of 50 N by using a lever. Calculate the mechanical advantage of the lever.
mars1129 [50]

Answer:

load (l)=400N

Effort(E)=50N

mechanical advantage (MA)= load ÷Effort

(ma)=400÷50

(ma)=8

Explanation:

I copy pasted from the answer from the same question. Remember to first check if ur question is there

4 0
3 years ago
An aluminum wing on a passenger jet is 35 m long when its temperature is 17°C. At what temperature would the wing be 3 cm (0.03
Mnenie [13.5K]

Answer:

53.32°C

Explanation:

Length of the aluminium wing = 35 m

Change in length of aluminium wing = 0.03 m

The linear expansion coefficient of aluminium \alpha =23.6\times 10^{-6}/^{\circ}C

We know that change in length is given by \Delta L=L\alpha \Delta T

So 0.03=35\times 23.6\times 10^{-6}\Delta T

\Delta T=36.32^{\circ}C

So final temperature =T_I+\Delta T=17+36.32=53.3196^{\circ}C

5 0
3 years ago
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