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maria [59]
3 years ago
9

what relationship exists between the atomic number of an element and the number of protons in a neutral atom of an element?​

Physics
1 answer:
Misha Larkins [42]3 years ago
4 0

Answer:

Neutral atoms of an element contain an equal number of protons and electrons. The number of protons determines an element's atomic number (Z) and distinguishes one element from another. For example, carbon's atomic number (Z) is 6 because it has 6 protons.

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A(n) _____ is the smallest complete part of a compound.
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The answer to this is: a molecule
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A truck with 34-in.-diameter wheels is traveling at 55 mi/h. Find the angular speed of the wheels in rad/min, *hint convert mile
julia-pushkina [17]

Answer:

w =3416 rad/min  

Explanation:

The angular speed of the wheels in radians can be defined as follows:

w=\frac{s}{r}

where

w = angular speed

r = radius of the wheel

s =distance traveled per minute

in this case we have

r = 34/2 inches = 17 inches

s = (55 mi/hr) (5280 ft/mi) (12 in/ft) (1hr/60min) = 58,080 inches/min

Therefore, w = 58,080/ 17 = 3416 rad/min  

7 0
4 years ago
Another element is silvery-white with a shiny luster, is very brittle, and forms ions with a −2 charge. give one possible identi
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The element is magnesium ( Mg )
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3 years ago
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An atom that has 7 protons 7 electrons and 6 neutrons
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The atom carbon is the answer
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Atomic hydrogen produces a well-known series of spectral lines in several regions of the electromagnetic spectrum. Each series f
navik [9.2K]

Answer:

n₁ = 3

Explanation:

The energy of the states in the hydrogen atom is explained by the Bohr model, the transitions heal when an electron passes from a state of higher energy to another of lower energy,

       ΔE = E_{nf} - E₀ = - k²e² / 2m (1 / n_{f}²2 - 1 / n₀²)

The energy of this transition is given by the Planck equation

       E = h f = h c / λ

       h c / λ = -k²e² / 2m (1 / no ²- 1 / no²)

       1 / λ = Ry (1/ n_{f}² - 1 / n₀²)

Let's apply these equations to our case

     λ = 821 nm = 821 10⁻⁹ m

     E = h c / λ

     E = 6.63 10⁻³⁴ 3 10⁸/821 10⁻⁹

     E = 2.423 10⁻¹⁹ J

Now we can use the Bohr equation

Let's reduce to eV

       E = 2,423 10⁻¹⁹ J (1eV / 1.6 10⁻¹⁹) = 1,514 eV

       E_{nf} - E₀ = -13.606 (1 /  n_{f}² - 1 / n₀²)   [eV]

Let's look for the energy of some levels

n         E_{n} (eV)          E_{nf} - EE_{ni} (eV)

1         -13,606           E₂-E₁ = 10.20

2        -3.4015           E₃-E₂ = 1.89

3        -1.512              E₄- E₃ = 0.662

4        -0.850375

We see the lines of greatest energy for each possible series, the closest to our transition is n₁ = 3 in which a transition from infinity (n = inf) to this level has an energy of 1,512 eV that is very close to the given value

8 0
3 years ago
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