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4 years ago

our sun is considered average because its temperature and absolute magnitude place it in the __ range of the H-R diagram

Chemistry

1 answer:

Vlad [161]4 years ago

5 0

Answer:

middle

Explanation:

When the stars are plotted on the Hertzsprung-Russell diagram, most of them fall into the curve called the main sequence. The main sequence stars are 'average' because many stars fall into this category, and these stars burn hydrogen into helium in their core, and they are relatively young ( age of a few billion years) .

Our sun sits in the middle of the main sequence curve in the HR- diagram, which means the it is a yellow dwarf star with a surface temperature of about 6000 K, it has an average size, and it is hot enough for hydrogen fusion—in other words a typical star.

You might be interested in

Energy can be changed from potential to kinetic. A.True B.False

vampirchik [111]

Answer:

An object has potential energy (stored energy) when it is not in motion. Once a force has been applied or it begins to move the potential energy changes to kinetic energy (energy of motion).

Therefore, true. (Also would u mind giving brainliest, you don't have to hehe)

6 0

3 years ago

What would be the best method to separate this solid from the solution?

PolarNik [594]

The best way to separate out a precipitate is using vacuum filtration. Use water to rinse out the flask thoroughly and wash the precipitate, followed by a quick rinse with ethanol to help dry it. After a few minutes on the vacuum pump, the precipitate should be ready to scrape off. Also, centrifugation can be an option for small amounts especially if you just need the filtrate. For reasonable amounts, a Millipore setup or Gooch type crucible works nicely for quantitative analysis.

5 0

3 years ago

Which equation is used to help form the combined gas law?

kkurt [141]

Answer:

The ideal gas equation

Explanation:

The ideal gas equation is derived from the combination of three gas laws:

Boyle's law
Charles's law
Avogadro's law.

The ideal gas law is expressed mathematically as: PV=nRT where:

P is pressure

V is volume

n is the number of moles

R is the ideal gas law

T is temperature.

To obtain the combined gas law, we assume that n=1 and this gives:

$\frac{PV}{T}$ = R

Therefore:

$\frac{P_{1} V_{1} }{T_{1} }$ = $\frac{P_{2} V_{2} }{T_{2} }$

5 0

3 years ago

A presión de 3atm, 7L de un gas a temperatura constante experimenta un cambio ocupando un volumen de 0,5L ¿Cuál será la presión

pantera1 [17]

Answer:

La presión que ejerce es 42 atm.

Explanation:

La ley de Boyle relaciona la presión y el volumen y dice que el volumen ocupado por una determinada masa gaseosa a temperatura constante, es inversamente proporcional a la presión.

La ley de Boyle se expresa matemáticamente como:

P*V=k

Ahora es posible suponer que tienes un cierto volumen de gas V1 que se encuentra a una presión P1 al comienzo del experimento. Si varias el volumen de gas hasta un nuevo valor V2, entonces la presión cambiará a P2, y se cumplirá:

P1*V1= P2*V2

En este caso:

P1= 3 atm
V1= 7 L
P2= ?
V2= 0.5 L

Reemplazando:

3 atm* 7 L= P2* 0.5 L

Resolviendo:

$P2=\frac{3 atm*7 L}{0.5 L}$

P2= 42 atm

La presión que ejerce es 42 atm.

3 0

3 years ago

A student obtains a 10.0g sample of a white powder labeled as BaCl2. After completely dissolving the powder in 50.0mL of distill

LekaFEV [45]

Answer:

Whether barium chloride solution was pure

Explanation:

We may answer whether barium chloride was pure. The sequence of this experiment might be depicted by the following balanced chemical equations:

$BaCl_2 (aq)\rightarrow Ba^{2+} (aq) + 2 Cl^- (aq)$

$Ba^{2+} (aq) + SO_4^{2-} (aq)\rightarrow BaSO_4 (s)$

Having a total sample of 10.0 grams, we would firstly find the mass percentage of barium in barium chloride:

$\omega_{Ba^{2+}} = \frac{M_{Ba}}{M_{BaCl_2}} = \frac{137.327 g/mol}{208.23 g/mol\cdot 100\% = 65.95 \%$

This means in 10.0 g, we have a total of:

$m_{Ba^{2+}} = 10.0 g\cdot 0.6595 = 6.595 g$ of barium cations.

The precipitate is then formed and we measure its mass. Having its mass determined, we'll firstly find the percentage of barium in barium sulfate using the same approach:

$\omega_{Ba} = \frac{137.327 g/mol}{233.38 g/mol}\cdot 100\% = 58.84 \%$

Multiplying the mass we obtained by the fraction of barium will yield mass of barium in barium sulfate. Then:

if this number is equal to 6.595 g, we have a pure sample of barium chloride;
if this number is lower than 6.595 g, this means we have an impure sample of barium chloride, as we were only able to precipitate a fraction of 6.595 g.

3 0

3 years ago