Answer:
1.02 moles of AlCl3
Explanation:
Consider the balanced reaction equation shown below;
2Al(s) + 3CuCl2(aq) -------> 2AlCl3 (aq) + 3Cu(s)
This is the balanced reaction equation for the reaction going on above. Recall that the first step in solving any problem is to accurately put down the chemical reaction equation. This balanced reaction equation always serves a reliable guide in solving the problem at hand.
Given that;
3 moles of CuCl2 yields 2 moles of AlCl3
1.53 moles of CuCl2 yields 1.53 × 2 / 3 =1.02 moles of AlCl3
Answer:
instantaneous rate would be the term.
<u>Given:</u>
Mass of solvent water = 4.50 kg
Freezing point of the solution = -11 C
Freezing point depression constant = 1.86 C/m
<u>To determine:</u>
Moles of methanol to be added
<u>Explanation:</u>
The freezing point depression ΔTf is related to the molality m through the constant kf, as follows:
ΔTf = kf*m
where ΔTf = Freezing point of pure solvent (water) - Freezing pt of solution
ΔTf = 0 C - (-11.0 C) = 11.0 C
m = molality = moles of methanol/kg of water = moles of methanol/4.50 kg
11.0 = 1.86 * moles of methanol/4.50
moles of methanol = 26.613 moles
Ans: Thus around 26.6 moles of methanol should be added to 4.50 kg of water.
