This problem is giving information about the proton concentrations of three solutions at 25 °C. Despite they are not numerically given, we can propose three scenarios to see how to approach the question.
Let the following solutions to come up:
[H⁺] = 2.63x10⁻³ M
[H⁺] = 1.00x10⁻⁷ M
[H⁺] = 4.511x10⁻⁹ M
The first step, will be the calculation of the pH for each solution via:
pH = -log([H⁺])
So that they turn out to be:
pH = -log(2.63x10⁻³ M) = 2.580
pH = -log(1.00x10⁻⁷ M) = 7.000
pH = -log(4.511x10⁻⁹ M) = 8.3457
In such a way, since acidic solutions have a pH below 7, neutral have a pH equal to 7 and basic have it above 7, we infer the first one is acidic, second one is neutral and third one is basic.
Thus, you can reproduce this methodology with the proton concentrations you are given.
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Answer:
A. the rate of the acylation reaction being faster than the deacylation reaction.
Explanation:
Chymotrypsin belongs to a class of enzymes known as proteases; enzymes that catalyse the cleavage of peptide bonds by hydrolysis.
The mechanism of chymotrypsin catalysis occurs in two distinct phases; (1) an acylation phase where the peptide bond is cleaved and an ester linkage is formed between the peptide carbonyl carbon and the enzyme, (2) a deacylation phase where the ester linkage is hydrolyzed and the non-avylated enzyme is regenerated.
In studies by B.S. Hartley and B.A. Kilby in 1954 of chymotrypsin hydrolysis of the ester p-nitropheylacetate, as measured by the release of nitrophenol, it was discovered that it proceeded with a burst before leveling of to a slower rate. This burst was due to a rapid acylation of all the enzyme molecules with a slow deacylation limiting the turnover of the enzyme.
Similarly, the observation of burst kinetics in rapid kinetic studies of the hydrolysis of p-nitrophenylphosphate by chymotrypsin is due to the initial phase of acylation proceeding much faster than the later phase of deacylation of the enzyme.
Atoms are considered the smallest particles of an element because they are the basic unit. They cannot be broken down into any smaller substance.
Answer:
Number of half lives = 5
Explanation:
Given data:
Half life of oxygen = 2 min
Half lives occured in 10 min = ?
Solution:
Formula;
Number of half lives = Time elapsed / half life
by putting values,
Number of half lives = 10 min / 2 min
Number of half lives = 5
Answer: 1.5 moles O2
Explanation:
The number of moles of each reactant and product is the number in front to the molecule when the equation is balanced.
You know that 1 mole of O2 gives you 2 moles of H2O
So you can set up a proportion using that.
1 mole O2. X moles O2
-------------- = -------------------
2 moles H2O. 3 moles H2O
Then cross multiply
2x=3
X=3/2 Or 1.5
So you need 1.5 moles O2 to get 3 moles of H2O.