The velocity of sound in at 300C is 511.3 m/s.
Explanation:
The equation that gives the speed of sound in ar as a function of the air temperature is the following:
![v=(331.3+0.6T) m/s](https://tex.z-dn.net/?f=v%3D%28331.3%2B0.6T%29%20m%2Fs)
where
T is the temperature of the air, measured in Celsius degrees
In this problem, we want to find the speed of sound in ar for a temperature of
![T=300^{\circ}C](https://tex.z-dn.net/?f=T%3D300%5E%7B%5Ccirc%7DC)
Substituting into the equation, we find:
![v=331.3 + 0.6(300)=511.3 m/s](https://tex.z-dn.net/?f=v%3D331.3%20%2B%200.6%28300%29%3D511.3%20m%2Fs)
So, the velocity of sound in at 300C is 511.3 m/s.
Learn more about sound waves:
brainly.com/question/4899681
#LearnwithBrainly
Heat rises, and it is warmer at the equator, so I think warm air would rise at the equator and move towards the cooler poles.
The first thing you should know in this case is the following definition:
PV = nRT
Then, as the temperature is constant, then:
PV = k
Then, we have two states:
P1V1 = k
P2V2 = k
We can then equalize both equations:
P1V1 = P2V2
Substituting the values:
(1.25) * (101) = (2.25) * (P2)
Clearing P2:
P2 = ((1.25) * (101)) /(2.25)=56.11Kpa
answer:
the new pressure inside the jar is 56.11Kpa