Answer:
wavelength
Explanation:
the definition of wavelength is the distance between two consecutive waves. with that being said, the point from the crest of one wave to the crest of another would be wave length
Answer:
The correct option is;
C. 1 mile clear of clouds
Explanation:
Given that the indicated airspace location is at or below 700 feet AGL therefore, it is taken as being in the region of a class G airspace which covers the airspace regions from the base up to and equal to 1,200 feet beneath the class E airspace and the requirement for VFR flight for class G are 1 mile and clear of clouds.
The electric field points in the +x direction and the particle's charge is positive, therefore the electric force points in the +x direction.
The electric force acting on the particle is:
F = Eq
F is the electric force, E is the electric field strength, and q is the charge.
Given:
E = 1290N/C
q = 6.58×10⁻⁶C
F = 1290(6.58×10⁻⁶) = 8.49×10⁻³N
The net force points in the +x direction, yet its magnitude is smaller than the magnitude of the electric force, so the magnetic force must point in the -x direction with a magnitude equal to the difference between the electric force and net force:
8.49×10⁻³ - 6.17×10⁻³
= <em>2.32×10⁻³N</em>
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The particle's velocity lies in the x-y plane and the magnetic field points in the +z direction. The velocity is perpendicular to the magnetic field, therefore the magnitude of the magnetic force can be calculated by:
F = qvB
F is the magnetic force, q is the charge, v is the velocity, and B is the magnetic field strength.
Given values:
F = 2.32×10⁻³N (solved for previously)
q = 6.58×10⁻⁶C
B = 1.27T
Plug in the values and solve for v:
2.32×10⁻³ = 6.58×10⁻⁶v(1.27)
v = 278m/s
Answer: 17.5N
Explanation:
Given that,
spring constant (k) = 70N/m
Original length (lo) = 40 cm
New length (ln) = 15 cm
extension of spring (e) = new length - original length
i.e e = ln - lo
e = 15 cm - 40 cm
e = -25cm (the negative sign is negligible, just the same magnitude matters)
So, convert 25cm to metres
If 100cm = 1m
25cm = 25/100 = 0.25m
(Note that how hard the spring push refers to the Force, hence, find force.)
Now, apply the Hooke law (F = ke)
Force = spring constant x extension
F = 70N/m x 0.25m
F = 17.5N
Thus, the spring push with a force of 17.5N when compressed.