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Dafna11 [192]
3 years ago
5

You are doing an experiment to determine your reaction time. Your friend holds a ruler. You place your fingers near the sides of

the lower part of the ruler without touching it. The friend drops the ruler without warning you. You catch the ruler after it falls 11.3 cm . What was your reaction time? please show formulas and explanation step by step
Physics
2 answers:
olga2289 [7]3 years ago
4 0
I'm guessing that you mean like this:
-- The ruler is held with zero at the bottom, and the centimeter markings
    increase as you go up the ruler.
-- You place your fingers with the ruler and the zero mark between them.
-- The number where you catch the ruler is the distance it has fallen.

Then, all we have to find is the time it takes for the ruler to fall 11.3 cm .

Here's the formula for the distance an object falls from rest
in a certain time:

                Distance = (1/2) (gravity) (time)²

On Earth, the acceleration of gravity is 9.8 m/s².
So we can write ...

                              11.2 cm  =  (1/2) (9.8 m/s²) (time)²
or
                         0.112 meter  =  (4.9 m/s²) (time)²                      

Divide each side
by  4.9 m/s² :        (0.112 m) / (4.9 m/s²)  =  time²

                            (0.112 / 4.9)  sec²  =  time²

Square root
each side:            time = √(0.112/4.9  sec²)

                                  =  √ 0.5488 sec²

                                  =      0.74 second     (rounded)  

Nataliya [291]3 years ago
4 0

Answer:

0.152 seconds

Explanation:

Distance travelled by the ruler = 11.3 cm = s

Initial velocity of the ruler = 0 = u

Final velocity of the ruler = v

Time taken by you to catch the ruler = t

a = Acceleration due to gravity = 9.81 m/s²

Equation of motion

s=ut+\frac{1}{2}at^2\\\Rightarrow 0.113=0t+\frac{1}{2}9.81t^2\\\Rightarrow t^2=\frac{2\times 0.113}{9.81}\\\Rightarrow t=\sqrt{\frac{2\times 0.113}{9.81}}\\\Rightarrow t=0.152\ s

So, it took you 0.152 seconds to react to the ruler falling.

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lidiya [134]

Answer:

The velocity of the tuning fork sound is 317.4648 m/s

Explanation:

The given parameters are;

The frequency of the fork, f = 426.7 Hz

The length of the closed air column, L = 0.186 m

The diameter of the tube, d = 0.15 m

At the fundamental frequency in a closed tube, we have;

λ = 4·L

Where;

λ = The wavelength of the wave

L = The length of the tube

From the equation for the velocity of a wave, we have;

v = f·λ

Where;

v = The velocity of the (sound) wave

f = The frequency of the wave = 426.7 Hz

λ = 4·L = 4 × 0.186 m = 0.744 m

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An object travels in a circular path of radius 5.0 meters at a uniform speed of 10. m/s. What is the magnitude of the object's a
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I think F= mv²/r
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alina1380 [7]

Answer:

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Explanation:

The RV is travelling at a velocity of

v_{RV}=+60 km/h

Here we have taken the direction of motion of the RV as positive direction.

The boy sitting near the driver throws the ball back with speed of 25 km/h, so the velocity of the ball in the reference frame of the RV is

v_B = -25 km/h

with negative sign since it is travelling in the opposite direction relative to the RV. Therefore, this is the velocity measured by every observer in the reference frame of the RV: so the speed measured by the boys is

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Instead, a stationary observer outside the RV measures a velocity of the ball given by the algebraic sum of the two velocities:

v = +60 km/h + (-25 km/h) = +35 km/h

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Answer:

Explanation:

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