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marissa [1.9K]
3 years ago
6

Atoms containing the same number of protons and different numbers of neutrons are _____. (1 point)

Chemistry
2 answers:
Scilla [17]3 years ago
4 0

Answer:

isotopes

Explanation:

The atoms of an element that have same number of protons but different number of neutrons are called as the isotopes of that element.

For example: _{1}^{1}(\textrm{H}\text{protium})\text{and}_{1}^{2}\textrm{H}(\text{deuterium}) are the isotopes of Hydrogen

Ions are the charged species of an atom that are formed by the gain or loose of electrons.

For example: \text{Na}^{+}

Neutrons are the sub-atomic particles found inside the nucleus of an atom. They carry no charge.

Compounds are the substances that are formed when two or more atoms combine in a definite proportion.

For example: NaCl

Vadim26 [7]3 years ago
3 0
I believe that it could be isotopes
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A sample of O2 gas occupies a volume of 571 mL at 26 ºC. If pressure remains constant, what would be the new volume if the tempe
Vlad1618 [11]

Answer: The new volume at different given temperatures are as follows.

(a) 109.81 mL

(b) 768.65 mL

(c) 18052.38 mL

Explanation:

Given: V_{1} = 571 mL,       T_{1} = 26^{o}C

(a) T_{2} = 5^{o}C

The new volume is calculated as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{5^{o}C}\\V_{2} = 109.81 mL

(b) T_{2} = 95^{o}F

Convert degree Fahrenheit into degree Cesius as follows.

(1^{o}F - 32) \times \frac{5}{9} = ^{o}C\\(95^{o}F - 32) \times \frac{5}{9} = 35^{o}C

The new volume is calculated as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{35^{o}C}\\V_{2} = 768.65 mL

(c) T_{2} = 1095 K = (1095 - 273)^{o}C = 822^{o}C

The new volume is calculated as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{822^{o}C}\\V_{2} = 18052.38 mL

8 0
2 years ago
What is the formal charge on the hydrogen atom in hf?
stepladder [879]

The formal charge of H = +1, because F in compounds can have only -1.

4 0
2 years ago
Read 2 more answers
Determine the number of moles in 382.5g of CO-2
exis [7]

Answer: 8.691 mols of CO₂

Explanation:

To find the number of moles in a given grams, you want to use the molar mass.

Let's first find the molar mass of CO₂.

Carbon's molar mass is 12.011 g/mol

Oxygen's molar mass is 15.999 g/mol

To find molar mass of CO₂, we want to add up the molar mass of carbon and oxygen. Remember, there are 2 Oxygens so we need to mulitply that by 2.

12.011+2(15.999)=44.009 g/mol

Now that we have molar mass, we can convert 382.5 g to mols.

382.5g*\frac{1 mol}{44.009g} =8.691 mol

There are about 8.691 mols of CO₂.

5 0
3 years ago
Hydrogen is an element with two naturally occurring isotopes: 2 H and 3 H. This means that 2 H, which has a mass number of 2, ha
Dmitry_Shevchenko [17]

Answer:

TRUE.

Explanation:

Mass Number is the sum of protons and neutrons present in the nucleus of an atom. Isotopy is a phenonmenon that occurs when atoms of same elements have different mass number (Number of neutrons).

2H isotope has 1 proton and 1 neutron.

3H isotope has 1 proton and 2 neutrons.

This meeans 2H isotope has fewer neutrons when compared to the 3H isotope. The correct option is TRUE.

8 0
3 years ago
What is the empirical formula for a substance that is composed of 40.66% carbon, 8.53% Hydrogen,23.72% Nitrogen, and 27.09% Oxyg
prohojiy [21]

Answer:

THE EMPIRICAL FORMULA OF THE SUBSTANCE IS C2H5NO

Explanation:

The steps involved in calculating the empirical formula of this substance in shown in the table below:

Element                            Carbon           Hydrogen          Nitrogen         Oxygen

1. % Composition              40.66              8.53                 23.72                27.09

2. Mole ratio =

%mass/ atomic mass       40.66/12         8.53/1          23.72/14            27.09/16

                                       =  3.3883            8.53              1,6943             1.6931

3. Divide by smallest

value (0.6931)          3.3883/1.6931    8.53/1.6931    1.6943/1.6931   1.6931/1.6931

                               =      2.001                  5.038           1.0007                      1

4. Whole number ratio        2                       5                   1                               1

The empirical formula = C2H5NO

7 0
3 years ago
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