Question

Which equivalence factor set should you use to convert 126 g c to atoms c? (1 mol c/126 g c)(6.02 x 1023 atoms c/1 mol

Answer 1

Answer: The equivalence factor set that should be used is $\frac{126g}{12.01g}\times 6.022\times 10^{23}$

Explanation:

Molar mass of a substance is defined as the mass of one mole of a substance.

We know that:

Molar mass of carbon atom = 12.01 g/mol

Given mass of carbon atom = 126 grams

Applying unitary method:

12.01 grams of carbon occupies 1 mole

So, 126 grams of carbon will occupy = $\frac{1mol}{12.01g}\times 126g$

According to mole concept:

1 mole of an element contains $6.022\times 10^{23}$ number of atoms

So, $\frac{1mol}{12.01g}\times 126g$ of carbon will contain = $\frac{1mol}{12.01g}\times 126g\times \frac{6.022\times 10^{23}}{1mol}=\frac{126g}{12.01g}\times 6.022\times 10^{23}$ number of atoms

Hence, the equivalence factor set that should be used is $\frac{126g}{12.01g}\times 6.022\times 10^{23}$

Answer 2

For this you must Cross multiply and cancel any two units that are the same and diagonal from each other.

I attached a screenshot of my work. Hopefully it all makes sense.