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ratelena [41]
3 years ago
9

A 50 g sample of an unknown metal is heated to 90.0C. It is placed in a perfectly insulated container along with 100 g of water

at an initial temperature of 20C. After a short time, the temperature of both the metal and water become equal at 25C. The specific heat of water is 4.18 J/gC in this temperature range. What is the specific heat capacity of the metal?
Chemistry
2 answers:
sergejj [24]3 years ago
4 0
Q unknown = -Q H2O
Q H2O= (100g x 4.18 J/g C x (25C - 20C)
Q H2O = 2090J

-2090J = (50g x c x (25C-90C)
-2090J = -3250c
.64 = c

I am a high school student and have done this problem a few months ago for my test, hope this helps
11Alexandr11 [23.1K]3 years ago
3 0
You're answer will be 0.64 just took a test and got it correct
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