Question

A 50 g sample of an unknown metal is heated to 90.0C. It is placed in a perfectly insulated container along with 100 g of water at an initial temperature of 20C. After a short time, the temperature of both the metal and water become equal at 25C. The specific heat of water is 4.18 J/gC in this temperature range. What is the specific heat capacity of the metal?

Answer 1

Q unknown = -Q H2O
Q H2O= (100g x 4.18 J/g C x (25C - 20C)
Q H2O = 2090J

-2090J = (50g x c x (25C-90C)
-2090J = -3250c
.64 = c

I am a high school student and have done this problem a few months ago for my test, hope this helps

Answer 2

You're answer will be 0.64 just took a test and got it correct