1.41 × 10³⁰ MeV
As we know, E=mc², where E is energy, m is mass and c is the speed of light(i.e. 3×10⁸ m/s).
Given mass = 2.5 kgs
∴ E = (2.5)×(3×10⁸)² J = 22.5×10¹⁶ J
As our answer is in joules so we have to convert it into mega electron volt(MeV)
1 J = 6.242 × 10¹² MeV
⇒ 22.5×10¹⁶ J = 22.5×10¹⁶ × (6.242 × 10¹²) MeV
⇒1.41 × 10³⁰ MeV
If you want to learn more about mass-energy conversions then you can check out this link:
https://brainly.in/question/9760064
B) moves with a constant speed until hitting the other end.
Meter and second is the correct answer.
Answer:
1 and 2
Explanation:
It is given that, force exerted by air is negligible in any way.
Also, it is given that channel is in the shape of a segment of a circle with its center at O.
When it is within the frictionless channel at position 'Q',
A gravity exerts force on the ball in the downward direction. On the other hand, the channel pointing from Q to O also exerts a force on the ball.
However, there is no any force in the direction of motion. On the other hand, he channel pointing from O to Q does not exert a force on the ball.
Answer:
ans: 4.34 × 10^(-9) N
Explanation:
mass of Mya say (m) = 65 kg
mass of spaceship say (M) = 1600 kg
universal gravitational constant(G) =6.67 × 10^(-11) Nm²/kg²
separation distance (d) = 4m
so,
gravitational force (F)= GMm/d²
=( 6.67 × 65 × 1600) / ( 10¹¹ × 4²)
= 4.34 × 10⁴ / 10¹³
= 4.34 × 10^(-9) N
