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Jobisdone [24]
3 years ago
12

Which of the following is the correct relationship among the acceleration, velocity, and position?

Physics
2 answers:
zepelin [54]3 years ago
8 0

Answer:

option (1)

Explanation:

Acceleration is defined as the rate of change of velocity with respect to time.

a = dv / dt

where, dv is the change in velocity and dt is the change in time.  

So, a = \frac{dv}{dt}\times \frac{ds}{ds}

a = \frac{dv}{ds}\times \frac{ds}{dt}

So, a ds = v dv

Thus, option (1) is correct.

Damm [24]3 years ago
5 0

Answer:1

Explanation:

If

s=displacement

v=velocity of particle

a=acceleration of particle

acceleration can be written as rate of change of velocity

so a=\frac{\mathrm{d} v}{\mathrm{d} t}

multiply and divide by ds

a=\frac{\mathrm{d} v}{\mathrm{d} t}\times \frac{ds}{ds}

a=\frac{\mathrm{d} v}{\mathrm{d} s}\times \frac{\mathrm{d} s}{\mathrm{d} t}

a=v\frac{\mathrm{d} v}{\mathrm{d} s}

ads=vdv

option 1 is correct

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