<span>Fusion produces large amounts of energy, and the fuel is found on Earth.</span>
Question
Rutherford tracked the motion of tiny, positively charged particles shot through a thin sheet of gold foil. Some particles travelled in a straight line and some were deflected at different angles.
Which statement best describes what Rutherford concluded from the motion of the particles?
A) Some particles travelled through empty spaces between atoms and some particles were deflected by electrons.
B) Some particles travelled through empty parts of the atom and some particles were deflected by electrons.
C) Some particles travelled through empty spaces between atoms and some particles were deflected by small areas of high-density positive charge in atoms.
D) Some particles travelled through empty parts of the atom and some particles were deflected by small areas of high-density positive charge in atoms.
Answer:
The right answer is C)
Explanation:
In the experiment described above, a piece of gold foil was hit with alpha particles, which have a positive charge. Alpha particles <em>α</em> were used because, if the nucleus was positive, then it would deflect the positive particles. The principles of physics posit that electric charges of the same orientation repel.
So most as expected some of the alpha particles went right through meaning that the gold atoms comprised mostly empty space except the areas that were with a dense population of positive charges. This area became known as the "nucleus".
Due to the presence of the positive charges in the nucleus, some particles had their paths bent at large angles others were deflected backwards.
Cheers!
Does height or distance affect impact?
You can test that and do your project about that or you can grow algae
Answer:
d = 1.13*10^{-4}m = 0.113mm
Explanation:
To find the minimum diameter, that allow to antiproton circulate in the chamber without touching the walls, you use the following formula for the radius of the trajectory of a charged particle in a constant magnetic field.
(1)
r: radius of the trajectory
m: mass of the antiproton = 9.1*10-31 kg
v: velocity of the antiproton = 4.0*10^4 m/s
B: magnitude of the magnetic field = 4.0mT = 4.0*10^-3 T
q: charge of the antiproton = +1.6*10^{-19}C
You replace the values of the parameters in (1):
Then, the diameter of the chamber must be, at least:
d=2r = 2(5.68*10^-5) = 1.13*10^{-4}m = 0.113mm
