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Alex787 [66]
3 years ago
8

Protein synthesis is vital for cell growth and metabolism. Transcription and translation are known as the central dogma of biolo

gy in which proteins are synthesized from DNA. How is transcription similar to translation in terms of base pairing? A) in transcription, RNA is formed; in translation, a polypeptide is formed B) transcription starts at the promoter; translation begins at the start codon C) in transcription, DNA binds to mRNA; in translation, codons bind to anti-codons D) in transcription, C pairs with G and A pairs with T to make mRNA; in translation, A pairs with U and G pairs with C to make tRNA
Physics
2 answers:
uranmaximum [27]3 years ago
8 0

Transcription and translation are very similar in terms of pairing. In transcription, DNA must bind with mRNA to make a transcript to send outside of the nucleus. In translation, codons bind with anti-codons to make amino acids which then form proteins.


Liono4ka [1.6K]3 years ago
6 0
I  think the answer is D i'm not for sure tho
 

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The acceleration vector of a particle in projectile motion ________.
Alex73 [517]

Answer:

Points downward, and its magnitude is 9.8 m/s^2

Explanation:

The motion of a projectile consists of two independent motions:

- A uniform horizontal motion, with constant velocity and zero acceleration. In fact, there are no forces acting on the projectile along the horizontal direction (if we neglect air resistance), so the acceleration along this direction is zero.

- A vertical motion, with constant acceleration g = 9.8 m/s^2 towards the ground (downward), due to the presence of gravity wich "pulls" the projectile downward.

The total acceleration of the projectile is given by the resultant of the horizontal and vertical components of the acceleration. But we said that the horizontal component is zero, therefore the total acceleration corresponds just to its vertical component, therefore it is a vector with magnitude 9.8 m/s^2 which points downward.

4 0
3 years ago
Which one of the statements below is true about mechanical waves?
TEA [102]
They require a medium to travel through
5 0
2 years ago
1. A 4000-kg truck traveling with a velocity of 20 m/s due south collides headon with a 1350-kg car traveling with a velocity of
velikii [3]

(a) The momentum of each vehicle prior to collision is 80000 kgm/s for truck and 13500 kgm/s for car.

(b) The size of momentum is 93500 kgm/s and it will be directed towards South.

Explanation:

The mass of the truck moving due south is given as 4000 kg and the speed is 20 m/s. Similarly, the mass of the car moving due north is 1350 kg and the speed is 10 m/s.

(a) Then the momentum of each vehicle can be obtained by the product of mass with their respective speed.

Momentum of truck = Mass * Speed = 4000 * 20 =80000  kgm/s

Similarly, the momentum of car will be

Momentum of car = 1350 * 10 = 13500 kgm/s

So, the momentum of each vehicle prior to collision is 80000 kgm/s for truck and 13500 kgm/s for car.

(b) Since, after collision, the vehicles stick together, the momentum after collision will be equal to the total momentum of both the vehicles before collision. This is because, it will obey conservation of momentum.

Momentum of vehicles after collision = total momentum before collision

Momentum after collision = 80000+13500 = 93500 kgm/s.

The direction of the vehicles after collision will be towards south as the mass and speed of the truck is greater than car. So the impact or force exerted on the car by the truck will be greater and thus both the vehicles will be directed towards south after collision.

Thus, the size of momentum is 93500 kgm/s and it will be directed towards South.

4 0
3 years ago
The temperature of a body falls from 30°C to 20°C in 5 minutes. The air
natulia [17]

Answer:

15.88°C I am not 100% sure this is right but I am 98% sure this IS right

7 0
2 years ago
Ted Clubber Lang. A hook in boxing primarily involves horizontal flexion of the shoulder while maintaining a constant angle at t
il63 [147K]

Answer:

15 m/s or 1500 cm/s

Explanation:

Given that

Speed of the shoulder, v(h) = 75 cm/s = 0.75 m/s

Distance moved during the hook, d(h) = 5 cm = 0.05 m

Distance moved by the fist, d(f) = 100 cm = 1 m

Average speed of the fist during the hook, v(f) = ? cm/s = m/s

This can be solved by a very simple relation.

d(f) / d(h) = v(f) / v(h)

v(f) = [d(f) * v(h)] / d(h)

v(f) = (1 * 0.75) / 0.05

v(f) = 0.75 / 0.05

v(f) = 15 m/s

Therefore, the average speed of the fist during the hook is 15 m/s or 1500 cm/s

6 0
3 years ago
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