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Alex787 [66]
3 years ago
8

Protein synthesis is vital for cell growth and metabolism. Transcription and translation are known as the central dogma of biolo

gy in which proteins are synthesized from DNA. How is transcription similar to translation in terms of base pairing? A) in transcription, RNA is formed; in translation, a polypeptide is formed B) transcription starts at the promoter; translation begins at the start codon C) in transcription, DNA binds to mRNA; in translation, codons bind to anti-codons D) in transcription, C pairs with G and A pairs with T to make mRNA; in translation, A pairs with U and G pairs with C to make tRNA
Physics
2 answers:
uranmaximum [27]3 years ago
8 0

Transcription and translation are very similar in terms of pairing. In transcription, DNA must bind with mRNA to make a transcript to send outside of the nucleus. In translation, codons bind with anti-codons to make amino acids which then form proteins.


Liono4ka [1.6K]3 years ago
6 0
I  think the answer is D i'm not for sure tho
 

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If y(t)y(t) describes the position with time, what is the proper formula for velocity with time? (Recall velocity is related to
PilotLPTM [1.2K]

Answer:

Although this question is not complete, I would give a general solution to this kind of problems.

If y(t) describes the position of a body with time such that

y(t) = at^(n) + bt^(m) + C

Then

V(t) = dy(t)/dt = ant^(n-1) + bmt^(m-1)

Explanation:

As an example supplies the position of a particle is given by

y(t) = 4t³- 3t² + 9

V(t) = 4x3t²- 3x2t¹

V(t) = d(t)/dt = 12t² - 6t.

Another example,

If y(t) = 15t³ - 2t² + 30t -80

V(t) = d(t)/dt = 15x3t² - 4t +30 = 45t² + 4t + 30.

Basically, in the equations above the powers of t reduces by one when computing the velocity function from y(t) by differentiation (calculating the derivative of y(t)). The constant term C (9 and 80 in the functions of y(t) in examples 1and 2 above) reduces to zero because the derivative of a constant (and ordinary number without the t attached to it) is always zero.

One last example,

y(t) = 2t^6 -3t²

V(t) = d(t)/dt = 12t^5 - 6t

6 0
4 years ago
A spotlight on the ground is shining on a wall 24m away. If a woman 2m tall walks from the spotlight toward the building at a sp
Lubov Fominskaja [6]

Answer:

\dfrac{dy}{dt}=-0.059\ m/s

Explanation:

It is given that,

Distance between the spotlight and the wall, y = 24 m

Height of the woman, h = 2 m

The woman walks toward the building at the rate of 0.6 m/s, \dfrac{dx}{dt}=0.6\ m/s

In the attached figure, triangle ABC and MNC are similar. So,

\dfrac{2}{y}=\dfrac{x}{24}............(1)

y=\dfrac{48}{x}

When she is 2 meters from the building. So x = 24-2 = 22 m

y=\dfrac{48}{22}=2.18\ m

Differentiating equation (1) i.e.

xy=48

x.\dfrac{dy}{dt}+y.\dfrac{dx}{dt}=0

22.\dfrac{dy}{dt}+2.18\times 0.6=0

\dfrac{dy}{dt}=-0.059\ m/s

So, her shadow is decreasing at the rate of 0.059 m/s. Hence, this is the required solution.                                

7 0
4 years ago
A 3.0 pF capacitor consists of two parallel plates that have surface charge densities of 1.0 nC/mm2 . If the potential between t
Archy [21]

Answer:

A=81mm^2

Explanation:

We know that for a capacitor Q=CV, where <em>Q </em>is the charge of one plate, <em>C</em> the capacitance and <em>V</em> the potential between the plates.

We also know that Q=\sigma A, since \sigma is the surface charge density and <em>A</em> the area of the plate (both equal in our case).

Putting all together:

A=\frac{CV}{\sigma}

Which for our values is:

A=\frac{(3\times10^{-12}F)(27\times10^3V)}{1\times10^{-9}C/mm^2}=81mm^2

Where we notice that the S.I. units combination FV/C must not have units (we can verify it directly from their definitions or we notice that mm^2 is enough to describe an area).

8 0
3 years ago
Sherita has a mass of 50 kg and slowly climbs up a 5 m high flight of stairs how much work dose sherita do in ascending the stai
elixir [45]
Work done = Mass * displacement 
W = 50 * 5 = 250 watts

In short, Your Answer would be 250 watts

Hope this helps!
4 0
3 years ago
Forecasting the time of, location, and magnitude of a seismic event does not prevent
Drupady [299]
<span>Forecasting the time of, location, and magnitude of a seismic event does not prevent
the event from happening, but it can help us reduce the destruction caused by
A) earthquakes.</span>
4 0
3 years ago
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