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Luba_88 [7]
3 years ago
13

The equation shows lead reacting with sulfuric acid to produce lead sulfate and hydrogen gas. mc012-1.jpg Which type of chemical

reaction does this equation represent? synthesis decomposition single replacement double replacement
Chemistry
2 answers:
krok68 [10]3 years ago
4 0
Single replacement and I know that for sure if you need me to explain i can but its Single replacement <span />
zhannawk [14.2K]3 years ago
3 0

Answer:-

Single replacement

Explanation:-

The definition for single displacement reaction is the reaction where an element must displace another element from it's compound

The symbol for lead is Pb

The formula for lead sulfate is PbSO4.

The formula for sulfuric acid is H2SO4.

The formula for Hydrogen gas is H2.

The balanced chemical equation is

Pb + H2SO4 --> PbSO4 + H2

Here we can see that an element Pb is reacting with a compound H2SO4 and takes the place of H2 to form PbSO4.

Hence this is an example of single displacement reaction.

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Select the correct answer.
ser-zykov [4K]

Answer:

I think the answer would be option d.

hope it helps.

3 0
3 years ago
Suppose the half-life is 9.0 s for a first order reaction and the reactant concentration is 0.0741 M 50.7 s after the reaction s
bazaltina [42]

<u>Answer:</u> The time taken by the reaction is 84.5 seconds

<u>Explanation:</u>

The equation used to calculate half life for first order kinetics:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half-life of the reaction = 9.0 s

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{9}=0.077s^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}     ......(1)

where,

k = rate constant  = 0.077s^{-1}

t = time taken for decay process = 50.7 sec

[A_o] = initial amount of the reactant = ?

[A] = amount left after decay process =  0.0741 M

Putting values in equation 1, we get:

0.077=\frac{2.303}{50.7}\log\frac{[A_o]}{0.0741}

[A_o]=3.67M

Now, calculating the time taken by using equation 1:

[A]=0.0055M

k=0.077s^{-1}

[A_o]=3.67M

Putting values in equation 1, we get:

0.077=\frac{2.303}{t}\log\frac{3.67}{0.0055}\\\\t=84.5s

Hence, the time taken by the reaction is 84.5 seconds

6 0
3 years ago
How is electronegativity related to covalent bonding?
Zolol [24]

Answer:

Atoms must have similar electronegativities in order to share electrons in a covalent bond.

Explanation:

Covalent bonding is one of the bondings that occurs between the atoms of elements. It is the bonding in which atoms share their valence electrons with one another. However, the ELECTRONEGATIVITY, which is the ability of an atom to be attracted to electrons play a major role in the formation of covalent bonds.

When atoms of different electronegativities combine, the more electronegative atom pulls more electrons towards itself, hence, an IONIC bond is formed. However, when the electronegativities of the atoms are similar, the sharing of their electrons becomes stronger. Hence, ATOMS MUST HAVE SIMILAR ELECTRONEGATIVITIES in order to share electrons in a covalent bond.

5 0
3 years ago
Read 2 more answers
What happens to the hydrogen ion (H+) concentration as an aqueous
padilas [110]

Answer:

Explanation:

It can be determined by measuring the Ph. D is incorrect.

C: is wrong because if you are making something acidic, you are increasing the H+

B: is the correct answer.

A: pH decreases. H+ increases which makes the Ph decrease. It is an oddity of the formula that makes this happen.

7 0
2 years ago
Read 2 more answers
Which aldehyde is an intermediate in the reduction of ethyl benzoate with lithium aluminum hydride?
garri49 [273]

Answer:

tetrahedral aldehyde

Explanation:

  1. The reaction begins with a hydride nucleophile reacting with the ester carbonyl carbon to form the tetrahedral intermediate.
  1. The carbonyl reforms to produce an aldehyde with the loss of the alkoxide ion.
  2. The resulting aldehyde undergoes a subsequent reaction with a hydride nucleophile to form another tetrahedral intermediate. The carbonyl is not able to reform, because there are no stable leaving groups.
  3. Therefore, the tetrahedral intermediate is protonated to produce a primary alcohol.
6 0
3 years ago
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