Answer:
CO₂
Explanation:
Carbon dioxide is a covalent compound. Two double bonds are formed between two oxygen atoms and one carbon atom. O=C=O
The covalent bond between them are polar.
Covalent bond:
It is formed by the sharing of electron pair between bonded atoms.
The atom with larger electronegativity attract the electron pair more towards it self and becomes partial negative while the other atom becomes partial positive.
For example:
In carbondioxide the electronegativity of oxygen is 3.44 and carbon is 2.55. That's why electron pair attracted more towards oxygen, thus oxygen becomes partial negative and carbon becomes partial positive. The electronegativity difference is 0.89 that's why it is polar covalent bond.
0.1 mol/L
. The concentration of the HCl is 0.1 mol/L
a) Write the <em>balanced chemical equation
</em>
HCl + NaOH → NaCl + H2O
b) Calculate the <em>moles of NaOH
</em>
Moles of NaOH = 0.050 L NaOH x (0.1 mol NaOH/1 L NaOH)
= 0.0050 mol NaOH
c) Calculate the <em>moles of HCl
</em>
Moles of HCl = 0.0050 mol NaOH x (1 mol HCl/1 mol NaOH)
= 0.0050 mol HCl
d) Calculate the <em>molar concentration</em> of the HCl
<em>c</em> = moles/litres = 0.0050 mol/0.050 L = 0.1 mol/L
Answer:
See the answer and the resolution below
Explanation:
The equation of the decomposition of magnesium carbonate is as follows:
Mg C03 (white solid) ---> C02 (gas) + Mg= (solid)
To calculate the mass of carbon dioxide produced, the weight of 1 mol of this and 1 mol of MgC03 is calculated. Then a simple rule of 3 is made.
Weight 1 mol of MgC03= Weight Mg + Weight C+ 3x(Weight 0)= 24,305g+ 12,017+3x (15,999)= 84, 318g/mol
Weight 1 mol of C02= Weight C + 2x(Weight 0)=12,017+2x (15,999)= 44, 008g/mol
84, 319 g MgC03------44,008g C02
36,0 g MgC03------X= (36,0 g MgC03x44,008g C02)/84, 319 g MgC03= 18,8 g C02
Answer:
-0.050 kJ/mol.K
Explanation:
- A certain reaction is thermodynamically favored at temperatures below 400. K, that is, ΔG° < 0 below 400. K
- The reaction is not favored at temperatures above 400. K, that is. ΔG° > 0 above 400. K
All in all, ΔG° = 0 at 400. K.
We can find ΔS° using the following expression.
ΔG° = ΔH° - T.ΔS°
0 = -20 kJ/mol - 400. K .ΔS°
ΔS° = -0.050 kJ/mol.K
