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ollegr [7]
3 years ago
11

What type of reproduction occurs in members of the bacteria kingdom?

Chemistry
1 answer:
Mamont248 [21]3 years ago
7 0

Answer:

Bacteria can use sexual and asexual repoduction

Explanation:

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What noble gas has the same electron configuration as the oxide ion?
Tems11 [23]
I love these type of questions :)

Final Answer: Neon
5 0
3 years ago
What phase of matter has enough kinetic energy to partially overcome the intermolecular attraction between the particles, allowi
cluponka [151]

The answer is; liquid phase

The characteristics described in the question are those of a liquid. The forces between liquid particles are weaker than the forces between solid particles because the particles are further apart. The particles are not held in a  fixed position in the structure hence it can flow and take the shape of the container in which it is in.


3 0
3 years ago
Read 2 more answers
An interpenetrating primitive cubic structure like that of CsCl with anions in the corners has an edge length of 664 pm. If the
san4es73 [151]

Answer:

the ionic radius of the anion r^- = 312.52 \ pm

Explanation:

From the diagram shown below :

The anion Cl^- is located at the corners

The cation Cs^+ is located at the body center

The Body diagonal length =  \sqrt{3 \ a }

∴ 2 \ r^+ \ + 2r^- \ = \sqrt{3 \ a}  \\ \\ r^+ +r^- = \frac{\sqrt{3}}{2} a

Given that :

\frac{r^+}{r^-} =0.84   (i.e the  ratio of the ionic radius of the cation to the ionic radius of

                 the anion )

0.84r^- \ + r^- \ = \frac{\sqrt{3}}{2}a  \\ \\  1.84 r^- = \frac{3}{2}a \\ \\ r^- = \frac{\sqrt{3}}{2*1.84}a

Also ; a =  664 pm

Then :

r^- = \frac{\sqrt{3} }{2*1.84}*664 \ pm\\ \\ r^- = 312.52 \ pm

Therefore,  the ionic radius of the anion r^- = 312.52 \ pm

4 0
3 years ago
What is the Pauli Exclusion Principle?
Fiesta28 [93]

Answer:

the answer is A An atomic orbital can only hold a maximum of 2 electrons, each with opposite spins

Explanation:

3 0
3 years ago
The equilibrium constant (K p) for the interconversion of PCl 5 and PCl 3 is 0.0121:
aksik [14]

Answer: At equilibrium, the partial pressure of PCl_{3} is 0.0330 atm.

Explanation:

The partial pressure of PCl_{3} is equal to the partial pressure of Cl_{2}. Hence, let us assume that x quantity of PCl_{5} is decomposed and gives x quantity of PCl_{3} and x quantity of Cl_{2}.

Therefore, at equilibrium the species along with their partial pressures are as follows.

                         PCl_{5}(g) \rightarrow PCl_{3}(g) + Cl_{2}(g)\\

At equilibrium:  0.123-x          x              x

Now, expression for K_{p} of this reaction is as follows.

K_{p} = \frac{[PCl_{3}][Cl_{2}]}{[PCl_{5}]}\\0.0121 = \frac{x \times x}{(0.123 - x)}\\x = 0.0330

Thus, we can conclude that at equilibrium, the partial pressure of PCl_{3} is 0.0330 atm.

4 0
3 years ago
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