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konstantin123 [22]
3 years ago
7

We have an object moving at 5 m/s with mass 5 kg. It undergoes a quick collision with some other object and now moves at 1 m/s.

What was the change in the objects momentum
Physics
1 answer:
andrey2020 [161]3 years ago
5 0

Answer:

-20 kg.m/s

Explanation:

We have an object moving at 5 m/s with mass 5 kg. The initial momentum is:

pi = m × vi

pi = 5 kg × 5 m/s = 25 kg.m/s

It undergoes a quick collision with some other object and now moves at 1 m/s. The final momentum is:

pf = m × vf

pf = 5 kg × 1 m/s = 5 kg.m/s

The change in the object's momentum is:

Δp = pf - pi

Δp = 5 kg.m/s - 25 kg.m/s = -20 kg.m/s

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Answer:

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Explanation:

Given data

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Answer:

f = 1.69*10^5 Hz

Explanation:

In order to calculate the frequency of the sinusoidal voltage, you use the following formula:

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you solve the equation (1) for f and replace the values of the other parameters:

f=\frac{V_L}{2\pi iL}=\frac{12.0V}{2\pi (2.4*10^{-3}A)(4.70*10^{-3}H)}=1.69*10^5Hz      

The frequency of the sinusoidal voltage is f

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7 0
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zaharov [31]

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Answer:

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Explanation:

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