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TiliK225 [7]
3 years ago
7

I need more help please with all of these problems

Chemistry
1 answer:
prohojiy [21]3 years ago
3 0

Answer:

I need points

Explanation:

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CaCl2<br> Ca +<br> CI2<br> Balance this equation
Elis [28]

To balance Ca + Cl2 = CaCl2 you'll need to be sure to count all of atoms on each side of the chemical equation.

Once you know how many of each type of atom you can only change the coefficients (the numbers in front of atoms or compounds) to balance the equation for Calcium + Chlorine gas.

3 0
3 years ago
When an oxygen atom forms an ion, it gains two electrons. What is the electrical charge of the oxygen ion?
bekas [8.4K]
D. 2- youre adding two negative charges to a neutral element
5 0
4 years ago
How many grams are in 32.2 L of CO2?
Naddika [18.5K]

Answer:

63.25 grams of CO₂

Explanation:

To convert from liters to grams, we first need to convert from liters to moles. To do this, we divide the liters by 22.4, the amount of liters of a gas per mole.

32.2 / 22.4

= 1.4375 moles of CO₂

Now we want to convert from moles to grams. To do this, we multiply the moles by the molar mass of CO₂. The total molar mass can be found on the periodic table by adding up the molar mass of carbon (12) and two oxygen (32).

12 + 32 = 44

Now we want to multiply the moles by the molar mass.

1.4375 • 44

= 63.25 grams of CO₂

This is your answer.

Hope this helps!

7 0
3 years ago
3. Suppose a student determined the empirical formula of the compound to be K3[Fe(C2O4)3] 2H2O, rather than the correct formula
yuradex [85]

Answer:

Explanation:

When determining empirical formulas of hydrates we have to find the mass of water which left the hydrate when heating The sample. This amount of water calculated will provide us with the correct ratio of moles water / moles anhydrate since moles water > moles anhydrate. The mistake might have been done while determining the water that left the sample so then we see and impropre result in ratios.

8 0
3 years ago
How many moles of ZnCl, will be produced from 23.0 g of Zn, assuming CuCl, is available in excess?
Dennis_Churaev [7]

Answer:

23 g of Zn will produce 0.352 mole of zinc chloride.      

Explanation:

Given data:

mass of Zn = 23 g

Moles of ZnCl = ?

Solution:

Chemical equation:

2Zn + CuCl₂ → 2ZnCl + Cu

Number of moles of Zn:

<em>Number of moles of Zn = mass/ molar mass</em>

Number of moles of Zn = 23 g / 65.38 g/mol

Number of moles of Zn = 0.352 mol

now we will compare the moles of ZnCl with Zn because it is limiting reactant.

                         Zn       :      ZnCl  

                         2         :        2

                         0.352 :        0.352

So 23 g of Zn will produce 0.352 mole of zinc chloride.      

7 0
4 years ago
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