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posledela
4 years ago
13

__ used to show the relationship between two variables (2 words)

Chemistry
1 answer:
Naya [18.7K]4 years ago
3 0
Scatter Plots. Scatter Plots show the relationship between two variables.
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Fill in the coefficients that will balance the following reaction: a0Na + a1H2O → a2NaOH + a3H2
Alexandra [31]
Hey there !  :

<span>2 Na + 2 H2O = 2 NaOH + 1 H<span>2

</span></span>Sodium<span> + </span>Dihydrogen Monoxide<span> = </span><span>Natriumhydroxid</span><span> + </span>Hydrogen

Coefficients:

Reagents  :  Na = 2
                    H2O = 2
   

Products :  NaOH = 2
                  H2 = 1
4 0
4 years ago
Read 2 more answers
If the oxidation number of an atom decreases, the atom has undergone oxidation.
Bumek [7]

Oxidation is a process when an atom, a group of atoms, or an ion loses electrons.

For example,

Cu⁰ -------> Cu⁺² + 2e⁻. This is an oxidation process.

As we can see an oxidation number was 0, and it became +2. The oxidation number is increased. Oxidation number of the atom, when an atom has undergone oxidation, increases.

So, answer is b.False.

8 0
3 years ago
Is baking soda a fine powder or is it coarse
sp2606 [1]
Baking soda is a fine powder because when you touch it the baking soda is very soft
8 0
4 years ago
Which of the following is considered an alternative energy resource?
ELEN [110]
B. Biomass

(I guess so cause other ones are already being used)
4 0
3 years ago
A 112. 6 g mass of unknown material is submersed in 102 ml of water to yield a final volume of 126 ml. What is the apparent dens
skad [1K]

The density of the unknown material is 0.213 ml/g

<h3>Apparent density of the unknown material</h3>

The apparent density of the unknown material is calculated as follows;

Volume of the unknown substance = 126 ml - 102 ml = 24 ml

Density of the unknown substance = mass/volume

Density of the unknown substance =  24 ml / 112.6 g

Density of the unknown substance = 0.213 ml/g

Thus, the density of the unknown material is 0.213 ml/g

Learn more about density here; brainly.com/question/6838128

#SPJ1                          

4 0
1 year ago
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