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posledela
3 years ago
13

__ used to show the relationship between two variables (2 words)

Chemistry
1 answer:
Naya [18.7K]3 years ago
3 0
Scatter Plots. Scatter Plots show the relationship between two variables.
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In what month does winter begin in the southern hemisphere
Katyanochek1 [597]

In the Southern Hemisphere this would be around June 20 and culminates on September 22.

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Help please thank u !!
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2nd law i think

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You are performing a titration of a triprotic acid, when you spill water on your lab notebook. you can read that: pka 1 = 1.40,
eimsori [14]
According to the PH formula:
PH= Pka +㏒ [strong base/weak acid]
when we have PH at the first equivalence =3.35 and the Pka1 = 1.4
So, by substitution, we can get the value of ㏒[strong base / weak acid]
3.35 = 1.4 + ㏒[strong base/ weak acid]
∴㏒[strong base/weak acid] = 3.35-1.4 = 1.95 
to get the Pka2 we will substitute with the value of ㏒[strong base/ weak acid] and the value of PH of the second equivalence point
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5 0
3 years ago
When the ground becomes saturated in a rain storm and the excess cannot be soaked up, the water will travel along the ground unt
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8 0
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Dolomite is a mixed carbonate of calcium and magnesium that decomposes to CO2 and the metal oxides MgO and CaO upon heating. Whe
kirill [66]

Answer:

47%

Explanation:

MgCO₃ (s) → MgO (s) + CO₂ (g)

CaCO₃ (s) → CaO (s) + CO₂ (g)

_______________________

MgCO₃ (s) + CaCO₃ (s) → MgO (s) + CaO (s) + 2CO₂ (g)

MgO: 40.3044 g/mol

MgCO₃: 84.3139 g/mol

CaO:56.0774 g/mol

CaCO₃: 100.0869 g/mol

CO₂: 44.01 g/mol

15.42 g is the total mass of dolomite.

7.85 g is the sum of MgO and CaO produced.

This means that 7.57 g of CO₂ were produced.

44.01 g CO₂_____ 1 mol

7.57 g CO₂ _____  x

x = 0.172 mol CO₂

Considering the global reaction, we had 0.172/2 = 0.086 mol of MgCO₃ in the original sample.

1 mol MgCO₃ _______ 84.3139 g

0.086 mol MgCO₃ ___ y

y = 7.25 g

15.42 g dolomite ______ 100%

7.25 g MgCO₃ ________ z

z = 47%

7 0
3 years ago
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