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3 years ago

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The mixing of which pair of reactants will result in a precipitation reaction? A. Ba(NO3)2(aq) + Na2CO3(aq) B. NH4Br(aq) + NH4I(

aq) C. K2SO4(aq) + Cu(NO3)2(aq) D. NaClO4(aq) + (NH4)2S(aq)

1 answer:

Semenov [28]3 years ago

8 0

Answer:

A. Ba(NO₃)₂(aq) + Na₂CO₃(aq)

Explanation:

The reaction between aqueous Ba(NO₃)₂ and Na₂CO₃ is a precipitation reaction.

The complete equation for the reaction is;

Ba(NO₃)₂(aq) + Na₂CO₃(aq) → BaCO₃(s) + NaNO₃(aq)

Barium carbonate is the precipitate formed during the reaction.
All nitrates are soluble in water and all salts of sodium are soluble in water, therefore, Ba(NO₃)₂, Na₂CO3, and NaNO₃ are soluble in water.
Precipitation reaction involves reaction of soluble salts to form a precipitate as one of the product.

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You have 1.2 L of air in a balloon 175 K. what is the new volume of the balloon when it is heated to 245 K

Marina86 [1]

Answer:

A) 1.68 L

Explanation:

Charles’ Law states that: at constant pressure, the volume is directly proportional to the temperature of the gas.

It can be expressed as: V₁T₂ = V₂T₁,

V₁ = 1.2 L, T₁ = 175.0 K, V₂ = ??? L, T₂ = 245.0 K.

∴ V₂ = V₁T₂/T₁ = (1.2 L)(245.0 K)/(175.0 K) = 1.68 L.

8 0

3 years ago

What is ΔE in kJ for a system that receives 1.79 kJ of heat from surroundings and has 4.51 kcal of work done on it at the same t

kenny6666 [7]

Answer: 20.7 kJ

Explanation:

According to first law of thermodynamics:

$\Delta E=q+w$

$\Delta E$ =Change in internal energy

q = heat absorbed or released

w = work done or by the system

w = work done on the system= $-P\Delta V$ {Work is done on the system is positive as the final volume is lesser than initial volume}

w = 4.51 kcal = $4.51\times 4.184kJ=18.9kJ$ (1kcal = 4.184kJ)

q = +1.79 kJ {Heat absorbed by the system is positive}

$\Delta E=+1.79+(18.9)=20.7kJ$

Thus $\Delta E$ for a system that receives 1.79 kJ of heat from surroundings and has 4.51 kcal of work done on it at the same time is 20.7 kJ

4 0

3 years ago

4. What is the substance called that dissolves the other substance in a solution?

blagie [28]

Answer:

Solvent

Explanation:

When one substance dissolves into another, a solution is formed. A solution is a homogeneous mixture consisting of a solute dissolved into a solvent

3 0

3 years ago

Which is one characteristic of hurricanes?

siniylev [52]

Given the following choices, determine which best suits as a characteristic of a hurricane.

Answer Choices:

A. Hurricanes occur mostly inland

B. Hurricanes create widespread damage

C. Hurricanes can only last for a short amount of time

D. Hurricanes gain strength after passing overland

Best Answer: B. Hurricanes can create widespread damage.

Reason: A would not be correct since it is more of a variable, due to the fact that hurricanes usually begin near the coastlines, hurricanes are in fact capable of moving inland for atleast 100 miles before it dies down to a tropical storm or depression.

C is not correct since hurricanes can last up to a whole week which is approximately 168 hours.

D is not correct since it is another variable in which hurricanes can decrease in strength if it comes into contact with cool and dry air which is the opposite of warm and moist which it needs in order to occur.

Therefore, the best choice is B. Hurricanes can create widespread damage, hurricanes can unleash a staggering arsenal of mother nature's strength and the most damage a hurricane has caused can go up to 125 billion USD in damages.

5 0

3 years ago

Read 2 more answers

When the following aqueous solutions are mixed together, a precipitate forms. Balance the net ionic equation in standard form fo

rewona [7]

<u>Answer:</u>

<u>For (a):</u> The balanced net ionic equation is $2Ag^{+}(aq)+S^{2-}(aq)\rightarrow Ag_2S(s)$ and the sum of coefficients is 4

<u>For (b):</u> The balanced net ionic equation is $Pb^{2+}(aq)+2Cl^{-}(aq)\rightarrow PbCl_2(s)$ and the sum of coefficients is 4

<u>For (c):</u> The balanced net ionic equation is $Ca^{2+}(aq)+CO_3^{2-}(aq)\rightarrow CaCO_3(s)$ and the sum of coefficients is

<u>For (d):</u> The balanced net ionic equation is $Ba^{2+}(aq)+2OH^{-}(aq)\rightarrow Ba(OH)_2(s)$ and the sum of coefficients is 4

<u>For (e):</u> The balanced net ionic equation is $Ag^{+}(aq)+Cl^{-}(aq)\rightarrow AgCl(s)$ and the sum of coefficients is 3

<u>Explanation:</u>

Net ionic equation is defined as the equations in which spectator ions are not included.

Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.

For (a): Sodium sulfide and silver nitrate

The balanced molecular equation is:

$Na_2S(aq)+2AgNO_3(aq)\rightarrow 2NaNO_3(aq)+Ag_2S(s)$

The complete ionic equation follows:

$2Na^{+}(aq)+S^{2-}(aq)+2Ag^+(aq)+2NO_3^{-}(aq)\rightarrow 2Na^+(aq)+2NO_3^-(aq)+Ag_2S(s)$

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

$2Ag^{+}(aq)+S^{2-}(aq)\rightarrow Ag_2S(s)$

Sum of the coefficients = [2 + 1 + 1] = 4

For (b): Lead(II) nitrate and sodium chloride

The balanced molecular equation is:

$2NaCl(aq)+Pb(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+PbCl_2(s)$

The complete ionic equation follows:

$2Na^{+}(aq)+2Cl^{-}(aq)+Pb^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^+(aq)+2NO_3^-(aq)+PbCl_2(s)$

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

$Pb^{2+}(aq)+2Cl^{-}(aq)\rightarrow PbCl_2(s)$

Sum of the coefficients = [2 + 1 + 1] = 4

For (c): Calcium nitrate and potassium carbonate

The balanced molecular equation is:

$K_2CO_3(aq)+Ca(NO_3)_2(aq)\rightarrow 2KNO_3(aq)+CaCO_3(s)$

The complete ionic equation follows:

$2K^{+}(aq)+CO_3^{2-}(aq)+Ca^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2K^+(aq)+2NO_3^-(aq)+CaCO_3(s)$

As potassium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

$Ca^{2+}(aq)+CO_3^{2-}(aq)\rightarrow CaCO_3(s)$

Sum of the coefficients = [1 + 1 + 1] = 3

For (d): Barium nitrate and sodium hydroxide

The balanced molecular equation is:

$2NaOH(aq)+Ba(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+Ba(OH)_2(s)$

The complete ionic equation follows:

$2Na^{+}(aq)+2OH^{-}(aq)+Ba^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^+(aq)+2NO_3^-(aq)+Ba(OH)_2(s)$

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions

The net ionic equation follows:

$Ba^{2+}(aq)+2OH^{-}(aq)\rightarrow Ba(OH)_2(s)$

Sum of the coefficients = [2 + 1 + 1] = 4

For (e): Silver nitrate and sodium chloride

The balanced molecular equation is:

$NaCl(aq)+AgNO_3(aq)\rightarrow NaNO_3(aq)+AgCl(s)$

The complete ionic equation follows:

$Na^{+}(aq)+Cl^{-}(aq)+Ag^{+}(aq)+NO_3^{-}(aq)\rightarrow Na^+(aq)+NO_3^-(aq)+AgCl(s)$

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

$Ag^{+}(aq)+Cl^{-}(aq)\rightarrow AgCl(s)$

Sum of the coefficients = [1 + 1 + 1] = 3

8 0

3 years ago