When a solution of cesium chloride (CsCl) is subjected to high-speed centrifugation, a stable density gradient is formed.

Consider a general reaction A ( aq ) enzyme ⇌ B ( aq ) A(aq)⇌enzymeB(aq) The Δ G ° ′ ΔG°′ of the reaction is − 5.980 kJ ⋅ mol −

Grace [21]

Answer : The value of $K_{eq}$ is, 11.2

The value of $\Delta G_{rxn}$ is -9.04 kJ/mol

Explanation :

The relation between the equilibrium constant and standard Gibbs free energy is:

$\Delta G^o=-RT\times \ln K_{eq}$

where,

$\Delta G^o$ = standard Gibbs free energy = -5.980 kJ/mol = -5980 J/mol

R = gas constant = 8.314 J/K.mol

T = temperature = $25^oC=273+25=298K$

$K_{eq}$ = equilibrium constant = ?

Now put all the given values in the above formula, we get:

$\Delta G^o=-RT\times \ln K_{eq}$

$-5980J/mol=-(8.314J/K.mol)\times (298K)\times \ln K_{eq}$

$K_{eq}=11.2$

Thus, the value of $K_{eq}$ is, 11.2

Now we have to calculate the $\Delta G_{rxn}$ .

The formula used for $\Delta G_{rxn}$ is:

The given reaction is:

$A(aq)\rightleftharpoons B(aq)$

$\Delta G_{rxn}=\Delta G^o+RT\ln Q$

$\Delta G_{rxn}=\Delta G^o+RT\ln \frac{[B]}{[A]}$ ............(1)

where,

$\Delta G_{rxn}$ = Gibbs free energy for the reaction = ?

$\Delta G_^o$ = standard Gibbs free energy = -30.5 kJ/mol

R = gas constant = $8.314\times 10^{-3}kJ/mole.K$

T = temperature = $37.0^oC=273+37.0=310K$

Q = reaction quotient

[A] = concentration of A = 1.8 M

[B] = concentration of B = 0.55 M

Now put all the given values in the above formula 1, we get:

$\Delta G_{rxn}=(-5980J/mol)+[(8.314J/mole.K)\times (310K)\times \ln (\frac{0.55}{1.8})$

$\Delta G_{rxn}=-9035.75J/mol=-9.04kJ/mol$

Therefore, the value of $\Delta G_{rxn}$ is -9.04 kJ/mol

3 0

3 years ago

The conditions at which the solid, liquid, and gaseous phases of a substance can exist in equilibrium with one another is called

AleksandrR [38]

The answer is: [D]: triple point .
______________________________________________________
Answer choice [A]: boiling point; refers to the temperature at which the equilibrium vapor pressure of the liquid equals the atmospheric pressure.
___________________________________________
Answer choice [B]: freezing point; refers to the temperature at which the solid and liquid are at equilibrium at one atm (1 ATM pressure).
___________________________________________
Answer choice [C]: sublimation point; refers to a change directly from the solid to the gaseous state without becoming liquid.
____________________________________________________

3 0

3 years ago

Masja [62]

Sorry, I need points to ask my questions...

6 0

3 years ago

What are the three things that are required for a celestial body to be considered a planet?

Nadusha1986 [10]

It is in orbit around the Sun.
It has sufficient mass to assume hydrostatic equilibrium (a nearly round shape).
It has “cleared the neighborhood” around its orbit.

5 0

3 years ago

How much heat is required to raise the temperature of 20 g of ice from -20.0 C to 0.0 C? The specific heat of ice is 2.03 J/(g•C

Arturiano [62]

Answer:

jikh

Explanation:

hhhhm

3 0

3 years ago