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3 years ago

Light acts like a

Chemistry

2 answers:

8_murik_8 [283]3 years ago

7 0

Particle
wave are the words you're looking for to fill in the blanks

lukranit [14]3 years ago

5 0

Answer:

Light acts like a particle when it bounces off surface and acts like a wave when it bends around objects

Explanation:

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Which of the following is an example of a chemical reaction?

FrozenT [24]

All of the above are chemical reactions.
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3 years ago

Draw the structure of tofacitinib with explicitly shown all carbon and hydogen atoms. identify the number of carbon atoms in tof

Andrew [12]

The structure of tofacitinib with explicit carbon and hydrogen is the first attached picture.

The number of carbon atoms in tofacitinib are 16.

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The structure of tofacitinib with all the filled hydrogen atoms is the second attached picture.

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3 years ago

Conserving water can save money while protecting the environment. True or False

blagie [28]

Answer: The given statement is true.

Explanation:

Water is a natural resource present in the nature and it is very precious as life without it is impossible.

So, when we unnecessarily use water then it means we are wasting a natural resource that cannot be reproduced again by human beings.

Therefore, more we are able to conserve water more we can protect other human life's and environment also.

If there is shortage of water then its prices will go high and hence we need to pay more for it.

Thus, we can conclude that the statement conserving water can save money while protecting the environment, is true.

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3 years ago

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For a process Arightwards harpoon over leftwards harpoonB, at 25 °C there is 10% of A at equilibrium while at 75 °C, there is 80

Lostsunrise [7]

This question is describing the following chemical reaction at equilibrium:

$A\rightleftharpoons B$

And provides the relative amounts of both A and B at 25 °C and 75 °C, this means the equilibrium expressions and equilibrium constants can be written as:

$K_1=\frac{90\%}{10\%}=9\\\\K_2=\frac{20\%}{80\%} =0.25$

Thus, by recalling the Van't Hoff's equation, we can write:

$ln(K_2/K_1)=-\frac{\Delta H}{R}(\frac{1}{T_2} -\frac{1}{T_1} )$

Hence, we solve for the enthalpy change as follows:

$\Delta H=\frac{-R*ln(K_2/K_1)}{(\frac{1}{T_2} -\frac{1}{T_1} ) }$

Finally, we plug in the numbers to obtain:

$\Delta H=\frac{-8.314\frac{J}{mol*K} *ln(0.25/9)}{[\frac{1}{(75+273.15)K} -\frac{1}{(25+273.15)K} ] } \\\\\\\Delta H=4,785.1\frac{J}{mol}$

Learn more:

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3 years ago

I HAVE ANSWER

Agata [3.3K]

11.2G is the answer to this problem.

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3 years ago

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