Answer:
20.5 torr
Explanation:
Given parameters:
Volume of tank = 15L
Pressure of tank = 8.2 x 10⁴torr
Volume of empty chamber = 6.0 x 10⁴L
Unknown:
New pressure of the gas in this chamber = ?
Solution:
To solve this problem, a good knowledge of the gas law will suffice here. Since pressure and volume relationships are under consideration, the Boyle's law is the proper gas law to apply.
Boyle's law states that "at constant temperature, the volume of fixed mass of gas is inversely proportional to the pressure of the gas".
Mathematically;
(Pressure x volume) of tank = (Pressure x volume ) of empty chamber
15 x 8.2 x 10⁴ = Pressure of empty chamber x 6 x 10⁴
Pressure of empty chamber = 20.5 torr
21) Ionic
22) Ionic
23) Covalent
24) Ionic ?
25) Ionic
26) Ionic
27) Ionic ?
28) Covalent
29) Ionic ?
30) Covalent
31) Ionic ?
32) Ionic ?
33) Covalent
34) Ionic ?
35) Ionic ?
36) Covalent ?
37) Covalent
38) Ionic ?
39) Ionic ?
40) Covalent
These answers are based on if there was a nonmetal and nonmetal it’s Covalent and if there was a metal and nonmetal it was Ionic I didn’t use the electro negativity for the answers that has more than two elements, if the answers had more than two elements they have a ? Next to their answer.
I HOPE THIS HELPS AND IF IM WRONG FEEL FREE TO COMMENT AND TELL ME SO
Answer:
6.022 x 1023 molecules = 1 Mole O2 = 22.4L
3.022 x 1023 molecules = 1/2 Mole O2 = 11.2L
The answer is 11.2 Litres
Explanation:
Mole-mole calculations are not the only type of calculations that can be performed using balanced chemical equations. Recall that the molar mass can be determined from a chemical formula and used as a conversion factor. We can add that conversion factor as another step in a calculation to make a mole-mass calculation, where we start with a given number of moles of a substance and calculate the mass of another substance involved in the chemical equation, or vice versa.
For example, suppose we have the balanced chemical equation
2 Al + 3 Cl 2 → 2 Alcoa
Suppose we know we have 123.2 g of Cl 2. How can we determine how many moles of Alcoa we will get when the reaction is complete? First and foremost, chemical equations are not balanced in terms of grams; they are balanced in terms of moles. So to use the balanced chemical equation to relate an amount of Cl 2 to an amount of Alcoa, we need to convert the given amount of Cl 2 into moles. We know how to do this by simply using the molar mass of Cl 2 as a conversion factor. The molar mass of Cl 2 (which we get from the atomic mass of Cl from the periodic table) is 70.90 g/mil. We must invert this fraction so that the units cancel properly:
Answer:
26 grams of D will be produced.
Explanation:
The reaction is given by:
A + B -----> C + D
Mass of A reacted = 21 g
Mass of B reacted = 22 g
Mass of C formed = 17 g
Mass of D formed = m =?
According to law of conservation of mass, the total mass of the reactants used is equal to the total mass of the product formed.
Then:
mass of A reacted + mass of B reacted = mass of C formed + mass of D formed
21 + 22 = 17 + m
m = 26 g
